I met some trouble with a javascript.
In fact I have in my database many records that are abreviations and ther equivalent,
for example, replace tel => telephone etc...
So I have this function
$('#tags').keyup(function(e){
var code = e.which ? e.which : e.keyCode;
console.log(code);
if (code == 'tel'){
var input = this.value;
input = input.substr(0, input.length -1);
console.log(input);
input += 'tel';
this.value = input;
}
});
Actualy this does not work the trouble is that I do not have aby mistakes
in the console of javascript.
Anykind of help will be much appreciated.
Kind regards.
SP.
This should work:
$('#tags').keyup(function(e){
var code = e.which ? e.which : e.keyCode;
var input = this.value;
if (input.indexOf('tel') != -1) {
this.value = this.value.replace(/\btel\b/gi,'telephone');
}
});
Here is a fiddle
When using keyup()
the event handler only returns the keycode of the pressed key. For instance an x results in e = 88.
Use $("#tags").val()
to get the value of the input element.
the keyCode
or which
property doesn't return a string, or even a single char. It returns the key code that represents the key that was struck by the client. If you want to get the corresponding char: String.fromCharCode(e.which || e.keyCode);
.
If the user hit on the a
key, for example, the keycode will be 97
, String.fromCharCode(97)
returns a
.
If you want to know weather or not the current value of the element contains the abreviation: tel
, what you'll need to do is this:
$('#tags').keyup(function(e)
{
this.value = this.value.replace(/\btel\b/gi,'telephone');
});
This is untested and very likely to need some more work, but AFAIK, you want to replace all occurrences of tel
by telephone
. The expression I use /\btel\b/
replaces all substrings tel
, provided they are preceded and followed by a word-boundary (to avoid replacing part of a word).
Not that the end of a string and a dash are both considered to be word boundaries, too. If I wanted to type television
, I'd end up typing telephoneevision
. To avoid this, you'll need a slightly more complex expression. here's an example how you can avoid JS from treating a dash as a boundary, just work on it to take string-endings into account, too
Update
Perhaps this expression isn't quite as easy as I thought, so here's what I'd suggest you use:
this.value = this.value.replace(/(?:(\-?\b))tel(?:(\b\-?.))/gi,function(all,b1,b2)
{
if (b1 === '-' || b2.charAt(0) === '-')
{//dash, don't replace
return all;
}//replace
return b1 + 'telephone' + b2;
});
Input: I need a tel, quickly ==> I need a telephone, quickly
I need a tel ==> I need a tel (if the user is still typing, don't replace, he could be typing telescope, replace on submit or on blur)
I want to book a hostel for tonight ==> I want to book a hostel for tonight
Visit Tel-Aviv ==> Visit Tel-Aviv
When using keypress this way the code
variable will contain the character code of the pressed character. Not the string of chars like the expected 'tel'. You could use onkeyup
/ onchange
event and check the val() of the input element and use replace()
to change the abbreviation to the intended string.
$('#tags').keyup(function(e){
var elem = $(this);
var input = elem.val();
// input = input.substr(0, input.length -1); // This might not be necessary
console.log(input);
// do the replacement
input = input.replace('tel','telephone');
elem.val(input);
}
});
Use replace method for replacing a word in string.
eg:
var str = "This is AIR";
var newstr = str.replace("AIR", "All India Radio");
console.log(newstr);