Another Repeated column in mapping for entity erro

问题:

Despite all of the others post, I can't find a solution for this error with GlassFish, on MacOSX, NetBeans 7.2.

Here the error :
SEVERE: Exception while invoking class org.glassfish.persistence.jpa.JPADeployer
prepare method
SEVERE: Exception while preparing the app
SEVERE: [PersistenceUnit: supmarket] Unable to build EntityManagerFactory

...

Caused by: org.hibernate.MappingException: Repeated column in mapping for entity:
com.supmarket.entity.Sale column: customerId
(should be mapped with insert="false" update="false")

Here the code :

Sale.java

@Entity
public class Sale {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    @Column(nullable=false)
    private Long idFromAgency;

    private float amountSold;

    private String agency;

    @Temporal(javax.persistence.TemporalType.DATE)
    private Date createdate;

    @Column(nullable=false)
    private Long productId;

    @Column(nullable=false)
    private Long customerId;

    @ManyToOne(optional=false)
    @JoinColumn(name="productId",referencedColumnName="id_product")
    private Product product;

    @ManyToOne(optional=false)
    @JoinColumn(name="customerId",referencedColumnName="id_customer")
    private Customer customer;


    public void Sale(){}    
    public void Sale(Long idFromAgency, float amountSold, String agency
            , Date createDate, Long productId, Long customerId){        
        ...
    }

    // then getters/setters
}

Customer.java

@Entity
public class Customer {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name="id_customer")
    private Long id_customer;

    @Column(nullable=false)
    private Long idFromAgency;

    private String  gender,
                    maritalState,
                    firstname,
                    lastname,
                    incomeLevel;

    @OneToMany(mappedBy="customer",targetEntity=Sale.class, fetch=FetchType.EAGER)
    private Collection sales;


    public void Customer(){}

    public void Customer(Long idFromAgency, String gender, String maritalState,
            String firstname, String lastname, String incomeLevel) {
        ...
    }

}

Product.java

public class Product {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name="id_product")
    private Long id_product;

    @Column(nullable=false)
    private Long idFromAgency;

    private String name;

    @OneToMany(mappedBy="product",targetEntity=Sale.class, fetch=FetchType.EAGER)
    private Collection sales;

    //constructors + getters +setters
}

回答1:

The message is clear: you have a repeated column in the mapping. That means you mapped the same database column twice. And indeed, you have:

@Column(nullable=false)
private Long customerId;

and also:

@ManyToOne(optional=false)
@JoinColumn(name="customerId",referencedColumnName="id_customer")
private Customer customer;

(and the same goes for productId/product).

You shouldn't reference other entities by their ID, but by a direct reference to the entity. Remove the customerId field, it's useless. And do the same for productId. If you want the customer ID of a sale, you just need to do this:

sale.getCustomer().getId()

回答2:

If you are stuck with a legacy database where someone already placed JPA annotations on but did NOT define the relationships and you are now trying to define them for use in your code, then you might NOT be able to delete the customerId @Column since other code may directly reference it already. In that case, define the relationships as follows:

@ManyToOne(optional=false)
@JoinColumn(name="productId",referencedColumnName="id_product", insertable=false, updatable=false)
private Product product;

@ManyToOne(optional=false)
@JoinColumn(name="customerId",referencedColumnName="id_customer", insertable=false, updatable=false)
private Customer customer;

This allows you to access the relationships. However, to add/update to the relationships you will have manipulate the foreign keys directly via their defined @Column values. It's not an ideal situation, but if you are handed this sort of situation, at least you can define the relationships so that you can use JPQL successfully.

回答3:

@Id
@Column(name = "COLUMN_NAME", nullable = false)
public Long getId() {
    return id;
}

@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, targetEntity = SomeCustomEntity.class)
@JoinColumn(name = "COLUMN_NAME", referencedColumnName = "COLUMN_NAME", nullable = false, updatable = false, insertable = false)
@org.hibernate.annotations.Cascade(value = org.hibernate.annotations.CascadeType.ALL)
public List<SomeCustomEntity> getAbschreibareAustattungen() {
    return abschreibareAustattungen;
}

If you have already mapped a column and have accidentaly set the same values for name and referencedColumnName in @JoinColumn hibernate gives the same stupid error

Error:

Caused by: org.hibernate.MappingException: Repeated column in mapping for entity: com.testtest.SomeCustomEntity column: COLUMN_NAME (should be mapped with insert="false" update="false")

回答4:

use this, is work for me:

@Column(name = "candidate_id", nullable=false)
private Long candidate_id;
@ManyToOne(optional=false)
@JoinColumn(name = "candidate_id", insertable=false, updatable=false)
private Candidate candidate;

回答5:

Take care to provide only 1 setter and getter for any attribute. The best way to approach is to write down the definition of all the attributes then use eclipse generate setter and getter utility rather than doing it manually. The option comes on right click-> source -> Generate Getter and Setter.