Sorting HashMap by values [duplicate]

问题:

This question already has an answer here:

• Sort a Map<Key, Value> by values 49 answers

I need to sort my HashMap according to the values stored in it. The HashMap contains the contacts name stored in phone.

Also I need that the keys get automatically sorted as soon as I sort the values, or you can say the keys and values are bound together thus any changes in values should get reflected in keys.

HashMap<Integer,String> map = new HashMap<Integer,String>();
map.put(1,\"froyo\");
map.put(2,\"abby\");
map.put(3,\"denver\");
map.put(4,\"frost\");
map.put(5,\"daisy\");

Required output:

2,abby;
5,daisy;
3,denver;
4,frost;
1,froyo;

回答1:

Assuming Java, you could sort hashmap just like this:

public LinkedHashMap<Integer, String> sortHashMapByValues(
        HashMap<Integer, String> passedMap) {
    List<Integer> mapKeys = new ArrayList<>(passedMap.keySet());
    List<String> mapValues = new ArrayList<>(passedMap.values());
    Collections.sort(mapValues);
    Collections.sort(mapKeys);

    LinkedHashMap<Integer, String> sortedMap =
        new LinkedHashMap<>();

    Iterator<String> valueIt = mapValues.iterator();
    while (valueIt.hasNext()) {
        String val = valueIt.next();
        Iterator<Integer> keyIt = mapKeys.iterator();

        while (keyIt.hasNext()) {
            Integer key = keyIt.next();
            String comp1 = passedMap.get(key);
            String comp2 = val;

            if (comp1.equals(comp2)) {
                keyIt.remove();
                sortedMap.put(key, val);
                break;
            }
        }
    }
    return sortedMap;
}

Just a kick-off example. This way is more useful as it sorts the HashMap and keeps the duplicate values as well.

回答2:

Try below code it works fine for me. You can choose both Ascending as well as descending order

import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;

public class SortMapByValue
{
    public static boolean ASC = true;
    public static boolean DESC = false;

    public static void main(String[] args)
    {

        // Creating dummy unsorted map
        Map<String, Integer> unsortMap = new HashMap<String, Integer>();
        unsortMap.put(\"B\", 55);
        unsortMap.put(\"A\", 80);
        unsortMap.put(\"D\", 20);
        unsortMap.put(\"C\", 70);

        System.out.println(\"Before sorting......\");
        printMap(unsortMap);

        System.out.println(\"After sorting ascending order......\");
        Map<String, Integer> sortedMapAsc = sortByComparator(unsortMap, ASC);
        printMap(sortedMapAsc);


        System.out.println(\"After sorting descindeng order......\");
        Map<String, Integer> sortedMapDesc = sortByComparator(unsortMap, DESC);
        printMap(sortedMapDesc);

    }

    private static Map<String, Integer> sortByComparator(Map<String, Integer> unsortMap, final boolean order)
    {

        List<Entry<String, Integer>> list = new LinkedList<Entry<String, Integer>>(unsortMap.entrySet());

        // Sorting the list based on values
        Collections.sort(list, new Comparator<Entry<String, Integer>>()
        {
            public int compare(Entry<String, Integer> o1,
                    Entry<String, Integer> o2)
            {
                if (order)
                {
                    return o1.getValue().compareTo(o2.getValue());
                }
                else
                {
                    return o2.getValue().compareTo(o1.getValue());

                }
            }
        });

        // Maintaining insertion order with the help of LinkedList
        Map<String, Integer> sortedMap = new LinkedHashMap<String, Integer>();
        for (Entry<String, Integer> entry : list)
        {
            sortedMap.put(entry.getKey(), entry.getValue());
        }

        return sortedMap;
    }

    public static void printMap(Map<String, Integer> map)
    {
        for (Entry<String, Integer> entry : map.entrySet())
        {
            System.out.println(\"Key : \" + entry.getKey() + \" Value : \"+ entry.getValue());
        }
    }
}

Edit: Version 2

Used new java feature like stream for-each etc

Map will be sorted by keys if values are same

 import java.util.*;
 import java.util.Map.Entry;
 import java.util.stream.Collectors;

 public class SortMapByValue

 {
    private static boolean ASC = true;
    private static boolean DESC = false;
    public static void main(String[] args)
    {

        // Creating dummy unsorted map
        Map<String, Integer> unsortMap = new HashMap<>();
        unsortMap.put(\"B\", 55);
        unsortMap.put(\"A\", 20);
        unsortMap.put(\"D\", 20);
        unsortMap.put(\"C\", 70);

        System.out.println(\"Before sorting......\");
        printMap(unsortMap);

        System.out.println(\"After sorting ascending order......\");
        Map<String, Integer> sortedMapAsc = sortByValue(unsortMap, ASC);
        printMap(sortedMapAsc);


        System.out.println(\"After sorting descending order......\");
        Map<String, Integer> sortedMapDesc = sortByValue(unsortMap, DESC);
        printMap(sortedMapDesc);
    }

    private static Map<String, Integer> sortByValue(Map<String, Integer> unsortMap, final boolean order)
    {
        List<Entry<String, Integer>> list = new LinkedList<>(unsortMap.entrySet());

        // Sorting the list based on values
        list.sort((o1, o2) -> order ? o1.getValue().compareTo(o2.getValue()) == 0
                ? o1.getKey().compareTo(o2.getKey())
                : o1.getValue().compareTo(o2.getValue()) : o2.getValue().compareTo(o1.getValue()) == 0
                ? o2.getKey().compareTo(o1.getKey())
                : o2.getValue().compareTo(o1.getValue()));
        return list.stream().collect(Collectors.toMap(Entry::getKey, Entry::getValue, (a, b) -> b, LinkedHashMap::new));

    }

    private static void printMap(Map<String, Integer> map)
    {
        map.forEach((key, value) -> System.out.println(\"Key : \" + key + \" Value : \" + value));
    }
}

回答3:

In Java 8:

Map<Integer, String> sortedMap = 
     unsortedMap.entrySet().stream()
    .sorted(Entry.comparingByValue())
    .collect(Collectors.toMap(Entry::getKey, Entry::getValue,
                              (e1, e2) -> e1, LinkedHashMap::new));

回答4:

You don\'t, basically. A HashMap is fundamentally unordered. Any patterns you might see in the ordering should not be relied on.

There are sorted maps such as TreeMap, but they traditionally sort by key rather than value. It\'s relatively unusual to sort by value - especially as multiple keys can have the same value.

Can you give more context for what you\'re trying to do? If you\'re really only storing numbers (as strings) for the keys, perhaps a SortedSet such as TreeSet would work for you?

Alternatively, you could store two separate collections encapsulated in a single class to update both at the same time?

回答5:

package com.naveen.hashmap;

import java.util.*;
import java.util.Map.Entry;

public class SortBasedonValues {

    /**
     * @param args
     */
    public static void main(String[] args) {

        HashMap<String, Integer> hm = new HashMap<String, Integer>();
        hm.put(\"Naveen\", 2);
        hm.put(\"Santosh\", 3);
        hm.put(\"Ravi\", 4);
        hm.put(\"Pramod\", 1);
        Set<Entry<String, Integer>> set = hm.entrySet();
        List<Entry<String, Integer>> list = new ArrayList<Entry<String, Integer>>(
                set);
        Collections.sort(list, new Comparator<Map.Entry<String, Integer>>() {
            public int compare(Map.Entry<String, Integer> o1,
                    Map.Entry<String, Integer> o2) {
                return o2.getValue().compareTo(o1.getValue());
            }
        });

        for (Entry<String, Integer> entry : list) {
            System.out.println(entry.getValue());

        }

    }
}

回答6:

map.entrySet().stream()
                .sorted((k1, k2) -> -k1.getValue().compareTo(k2.getValue()))
                .forEach(k -> System.out.println(k.getKey() + \": \" + k.getValue()));

回答7:

As a kind of simple solution you can use temp TreeMap if you need just a final result:

TreeMap<String, Integer> sortedMap = new TreeMap<String, Integer>();
for (Map.Entry entry : map.entrySet()) {
    sortedMap.put((String) entry.getValue(), (Integer)entry.getKey());
}

This will get you strings sorted as keys of sortedMap.

回答8:

I extends a TreeMap and override entrySet() and values() methods. Key and value need to be Comparable.

Follow the code:

public class ValueSortedMap<K extends Comparable, V extends Comparable> extends TreeMap<K, V> {

    @Override
    public Set<Entry<K, V>> entrySet() {
        Set<Entry<K, V>> originalEntries = super.entrySet();
        Set<Entry<K, V>> sortedEntry = new TreeSet<Entry<K, V>>(new Comparator<Entry<K, V>>() {
            @Override
            public int compare(Entry<K, V> entryA, Entry<K, V> entryB) {
                int compareTo = entryA.getValue().compareTo(entryB.getValue());
                if(compareTo == 0) {
                    compareTo = entryA.getKey().compareTo(entryB.getKey());
                }
                return compareTo;
            }
        });
        sortedEntry.addAll(originalEntries);
        return sortedEntry;
    }

    @Override
    public Collection<V> values() {
        Set<V> sortedValues = new TreeSet<>(new Comparator<V>(){
            @Override
            public int compare(V vA, V vB) {
                return vA.compareTo(vB);
            }
        });
        sortedValues.addAll(super.values());
        return sortedValues;
    }
}

Unit Tests:

public class ValueSortedMapTest {

    @Test
    public void basicTest() {
        Map<String, Integer> sortedMap = new ValueSortedMap<>();
        sortedMap.put(\"A\",3);
        sortedMap.put(\"B\",1);
        sortedMap.put(\"C\",2);

        Assert.assertEquals(\"{B=1, C=2, A=3}\", sortedMap.toString());
    }

    @Test
    public void repeatedValues() {
        Map<String, Double> sortedMap = new ValueSortedMap<>();
        sortedMap.put(\"D\",67.3);
        sortedMap.put(\"A\",99.5);
        sortedMap.put(\"B\",67.4);
        sortedMap.put(\"C\",67.4);

        Assert.assertEquals(\"{D=67.3, B=67.4, C=67.4, A=99.5}\", sortedMap.toString());
    }

}

回答9:

found a solution but not sure the performance if the map has large size, useful for normal case.

   /**
     * sort HashMap<String, CustomData> by value
     * CustomData needs to provide compareTo() for comparing CustomData
     * @param map
     */

    public void sortHashMapByValue(final HashMap<String, CustomData> map) {
        ArrayList<String> keys = new ArrayList<String>();
        keys.addAll(map.keySet());
        Collections.sort(keys, new Comparator<String>() {
            @Override
            public int compare(String lhs, String rhs) {
                CustomData val1 = map.get(lhs);
                CustomData val2 = map.get(rhs);
                if (val1 == null) {
                    return (val2 != null) ? 1 : 0;
                } else if (val1 != null) && (val2 != null)) {
                    return = val1.compareTo(val2);
                }
                else {
                    return 0;
                }
            }
        });

        for (String key : keys) {
            CustomData c = map.get(key);
            if (c != null) {
                Log.e(\"key:\"+key+\", CustomData:\"+c.toString());
            } 
        }
    }

回答10:

package SortedSet;

import java.util.*;

public class HashMapValueSort {
public static void main(String[] args){
    final Map<Integer, String> map = new HashMap<Integer,String>();
    map.put(4,\"Mango\");
    map.put(3,\"Apple\");
    map.put(5,\"Orange\");
    map.put(8,\"Fruits\");
    map.put(23,\"Vegetables\");
    map.put(1,\"Zebra\");
    map.put(5,\"Yellow\");
    System.out.println(map);
    final HashMapValueSort sort = new HashMapValueSort();
    final Set<Map.Entry<Integer, String>> entry = map.entrySet();
    final Comparator<Map.Entry<Integer, String>> comparator = new Comparator<Map.Entry<Integer, String>>() {
        @Override
        public int compare(Map.Entry<Integer, String> o1, Map.Entry<Integer, String> o2) {
            String value1 = o1.getValue();
            String value2 = o2.getValue();
            return value1.compareTo(value2);
        }
    };
    final SortedSet<Map.Entry<Integer, String>> sortedSet = new TreeSet(comparator);
    sortedSet.addAll(entry);
    final Map<Integer,String> sortedMap =  new LinkedHashMap<Integer, String>();
    for(Map.Entry<Integer, String> entry1 : sortedSet ){
        sortedMap.put(entry1.getKey(),entry1.getValue());
    }
    System.out.println(sortedMap);
}
}

回答11:

public static TreeMap<String, String> sortMap(HashMap<String, String> passedMap, String byParam) {
    if(byParam.trim().toLowerCase().equalsIgnoreCase(\"byValue\")) {
        // Altering the (key, value) -> (value, key)
        HashMap<String, String> newMap =  new HashMap<String, String>();
        for (Map.Entry<String, String> entry : passedMap.entrySet()) {
            newMap.put(entry.getValue(), entry.getKey());
        }
        return new TreeMap<String, String>(newMap);
    }
    return new TreeMap<String, String>(passedMap);
}

回答12:

import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map.Entry;

public class CollectionsSort {

    /**
     * @param args
     */`enter code here`
    public static void main(String[] args) {
        // TODO Auto-generated method stub

        CollectionsSort colleciotns = new CollectionsSort();

        List<combine> list = new ArrayList<combine>();
        HashMap<String, Integer> h = new HashMap<String, Integer>();
        h.put(\"nayanana\", 10);
        h.put(\"lohith\", 5);

        for (Entry<String, Integer> value : h.entrySet()) {
            combine a = colleciotns.new combine(value.getValue(),
                    value.getKey());
            list.add(a);
        }

        Collections.sort(list);
        for (int i = 0; i < list.size(); i++) {
            System.out.println(list.get(i));
        }
    }

    public class combine implements Comparable<combine> {

        public int value;
        public String key;

        public combine(int value, String key) {
            this.value = value;
            this.key = key;
        }

        @Override
        public int compareTo(combine arg0) {
            // TODO Auto-generated method stub
            return this.value > arg0.value ? 1 : this.value < arg0.value ? -1
                    : 0;
        }

        public String toString() {
            return this.value + \" \" + this.key;
        }
    }

}