I'm trying to convert a hex number to a character in C++.
I looked it up but I can't find an answer that works for me.
Here is my code:
char mod_tostring(int state, int index, int size) {
int stringAddress = lua_tolstring(state, index, 0);
const char* const Base = (const char* const)stringAddress;
return Base[0];
};
Base[0] would return a hex number like:
0000005B
If you go here http://string-functions.com/hex-string.aspx and put 0000005B as the input it outputs the character "[". How would I also output [?
To print a number as a character, you can either assign it to a char
variable or cast it to a char
type:
unsigned int value = 0x5B;
char c = static_cast<char>(value);
cout << "The character of 0x5B is '" << c << "` and '" << static_cast<char>(value) << "'\n";
You could also use snprintf
:
char text_buffer[128];
unsigned int value = 0x5B;
snprintf(&text_buffer[0], sizeof(text_buffer),
"%c\n", value);
puts(text_buffer);
Example program:
#include <iostream>
#include <cstdlib>
int main()
{
unsigned int value = 0x5B;
char c = static_cast<char>(value);
std::cout << "The character of 0x5B is '" << c << "` and '" << static_cast<char>(value) << "'\n";
std::cout << "\n"
<< "Paused. Press Enter to continue.\n";
std::cin.ignore(1000000, '\n');
return EXIT_SUCCESS;
}
Output:
$ ./main.exe
The character of 0x5B is '[` and '['
Paused. Press Enter to continue.
Try this:
std::cout << "0x%02hX" << Base[0] << std::endl;
Output should be: 0x5B assuming Base[0] is 0000005B.