MYSQL PHP - get float LIKE $float

问题:

I want to get rows with floats like my $float.

I used this code:

$float = $_GET['float'];

$requst = mysql_fetch_array(mysql_query("SELECT * FROM floats WHERE float LIKE'$float.%%%%%%%'"));

then I echoed all the rows with while:

while ($r = $request) {

    echo $a['float'];

}

but the page doesn't show anything. (YES, I typed in the address bar ?float=34 and there are floats like 34.****** in the table.)

What is the problem?

(PHP version 5.2, MYSQL version 5.0)

回答1:

Try This

$requst = mysql_query("SELECT * FROM floats WHERE float LIKE'$float.%%%%%%%'");
while ($r = mysql_fetch_array($request)) {

    echo $r['float'];

}

回答2:

How about select * from floats where floor(float) = $floor;?

回答3:

Your variable already has a decimal point in it.

"SELECT * FROM floats WHERE float LIKE '$float%'"

If your float is 34.567 your statement executes as find like '34.567.%' which isn't finding any results.

Edit: how about this then?

"SELECT * FROM floats WHERE abs(float-$float)<1;"

That will bring in anything within 1?

Having said that, although you can keep floats in mysql, it might be safer to keep them as decimals with a limited number of points after the decimal.