My current attempts at creating a random unicode character generate have failed with errors such as those mentioned in my other question here. It's obviously not as simple as just generating a random number.
Question: How can I generate a random unicode character in Swift?
Unicode Scalar Value
Any Unicode code point except high-surrogate and low-surrogate code
points. In other words, the ranges of integers 0 to D7FF and E000
to 10FFFF inclusive.
So, I've made a small code's snippet. See below.
This code works
func randomUnicodeCharacter() -> String {
let i = arc4random_uniform(1114111)
return (i > 55295 && i < 57344) ? randomUnicodeCharacter() : String(UnicodeScalar(i))
}
randomUnicodeCharacter()
This code doesn't work!
let N: UInt32 = 65536
let i = arc4random_uniform(N)
var c = String(UnicodeScalar(i))
print(c, appendNewline: false)
I was a little bit confused with this and this. [Maximum value: 65535]
static func randomCharacters(withLength length: Int = 20) -> String {
let base = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
var randomString: String = ""
for _ in 0..<length {
let randomValue = arc4random_uniform(UInt32(base.characters.count))
randomString += "\(base[base.index(base.startIndex, offsetBy: Int(randomValue))])"
}
return randomString
}
Here you can modify length (Int) and use this for generating random characters.