Possible Duplicate:
How can I run an external program from C and parse its output?
I want to run a command in linux and get the text returned of what it outputs, but I do not want this text printed to screen. Is there a more elegant way than making a temporary file?
You want the \"popen\" function. Here\'s an example of running the command \"ls /etc\" and outputing to the console.
#include <stdio.h>
#include <stdlib.h>
int main( int argc, char *argv[] )
{
FILE *fp;
char path[1035];
/* Open the command for reading. */
fp = popen(\"/bin/ls /etc/\", \"r\");
if (fp == NULL) {
printf(\"Failed to run command\\n\" );
exit(1);
}
/* Read the output a line at a time - output it. */
while (fgets(path, sizeof(path)-1, fp) != NULL) {
printf(\"%s\", path);
}
/* close */
pclose(fp);
return 0;
}
You need some sort of Inter Process Communication. Use a pipe or a shared buffer.
Usually, if the command is an external program, you can use the OS to help you here.
command > file_output.txt
So your C code would be doing something like
exec(\"command > file_output.txt\");
Then you can use the file_output.txt file.