jQuery: Can I call delay() between addClass() and

2019-01-01 04:50发布

问题:

Something as simple as:

$(\"#div\").addClass(\"error\").delay(1000).removeClass(\"error\");

doesn\'t seem to work. What would be the easiest alternative?

回答1:

You can create a new queue item to do your removing of the class:

$(\"#div\").addClass(\"error\").delay(1000).queue(function(next){
    $(this).removeClass(\"error\");
    next();
});

Or using the dequeue method:

$(\"#div\").addClass(\"error\").delay(1000).queue(function(){
    $(this).removeClass(\"error\").dequeue();
});

The reason you need to call next or dequeue is to let jQuery know that you are done with this queued item and that it should move on to the next one.



回答2:

AFAIK the delay method only works for numeric CSS modifications.

For other purposes JavaScript comes with a setTimeout method:

window.setTimeout(function(){$(\"#div\").removeClass(\"error\");}, 1000);


回答3:

I know this this is a very old post but I\'ve combined a few of the answers into a jQuery wrapper function that supports chaining. Hope it benefits someone:

$.fn.queueAddClass = function(className) {
    this.queue(\'fx\', function(next) {
        $(this).addClass(className);
        next();
    });
    return this;
};

And here\'s a removeClass wrapper:

$.fn.queueRemoveClass = function(className) {
    this.queue(\'fx\', function(next) {
        $(this).removeClass(className);
        next();
    });
    return this;
};

Now you can do stuff like this - wait 1sec, add .error, wait 3secs, remove .error:

$(\'#div\').delay(1000).queueAddClass(\'error\').delay(2000).queueRemoveClass(\'error\');



回答4:

jQuery\'s CSS manipulation isn\'t queued, but you can make it executed inside the \'fx\' queue by doing:

$(\'#div\').delay(1000).queue(\'fx\', function() { $(this).removeClass(\'error\'); });

Quite same thing as calling setTimeout but uses jQuery\'s queue mecanism instead.



回答5:

Delay operates on a queue. and as far as i know css manipulation (other than through animate) is not queued.



回答6:

Of course it would be more simple if you extend jQuery like this:

$.fn.addClassDelay = function(className,delay) {
    var $addClassDelayElement = $(this), $addClassName = className;
    $addClassDelayElement.addClass($addClassName);
    setTimeout(function(){
        $addClassDelayElement.removeClass($addClassName);
    },delay);
};

after that you can use this function like addClass:

$(\'div\').addClassDelay(\'clicked\',1000);


回答7:

Try this:

function removeClassDelayed(jqObj, c, to) {    
    setTimeout(function() { jqObj.removeClass(c); }, to);
}
removeClassDelayed($(\"#div\"), \"error\", 1000);


回答8:

delay does not work on none queue functions, so we should use setTimeout().

And you don\'t need to separate things. All you need to do is including everything in a setTimeOut method:

setTimeout(function () {
    $(\"#div\").addClass(\"error\").delay(1000).removeClass(\"error\");
}, 1000);


标签: jquery delay