Sample code trimmed down the the bare essentials to demonstrate question:
CREATE OR REPLACE FUNCTION mytest4() RETURNS TEXT AS $$
DECLARE
wc_row wc_files%ROWTYPE;
fieldName TEXT;
BEGIN
SELECT * INTO wc_row FROM wc_files WHERE "fileNumber" = 17117;
-- RETURN wc_row."fileTitle"; -- This works. I get the contents of the field.
fieldName := 'fileTitle';
-- RETURN format('wc_row.%I',fieldName); -- This returns 'wc_row."fileTitle"'
-- but I need the value of it instead.
RETURN EXECUTE format('wc_row.%I',fieldName); -- This gives a syntax error.
END;
$$ LANGUAGE plpgsql;
How can I get the value of a dynamically generated field name in this situation?
Use a trick with the function to_json()
, which for a composite type returns a json object with column names as keys:
create or replace function mytest4()
returns text as $$
declare
wc_row wc_files;
fieldname text;
begin
select * into wc_row from wc_files where "filenumber" = 17117;
fieldname := 'filetitle';
return to_json(wc_row)->>fieldname;
end;
$$ language plpgsql;
You don't need tricks. EXECUTE
does what you need, you were on the right track already. But RETURN EXECUTE ...
is not legal syntax.
CREATE OR REPLACE FUNCTION mytest4(OUT my_col text) AS
$func$
DECLARE
field_name text := 'fileTitle';
BEGIN
EXECUTE format('SELECT %I FROM wc_files WHERE "fileNumber" = 17117', field_name)
INTO my_col; -- data type coerced to text automatically.
END
$func$ LANGUAGE plpgsql;
Since you only want to return a scalar value use EXECUTE .. INTO ...
- optionally you can assign to the OUT
parameter directly.
RETURN QUERY EXECUTE ..
is for returning a set of values.
Use format()
to conveniently escape identifiers and avoid SQL injection. Provide identifiers names case sensitive! filetitle
is not the same as fileTitle
in this context.
- Are PostgreSQL column names case-sensitive?
Use an OUT
parameter to simplify your code.