Deserializing constructor hierarchy

(This question is very similar to this one, but this time I am calling the Parent deserializing constructor in the Child initialization list).

In a case where a Child adds no new data to be serialized, the Parent does not have a default constructor, I want to be able to serialize the Parent object directly as well as the Child, and neither the child nor the parent have default constructors, it seems like we should use the following pattern, where the child deserializing constructor initializes the parent (also using its deserializing constructor) in the initialization list:

#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>

#include <fstream>

class Parent
{
public:
    double mParentData;

    Parent(const double data) : mParentData(data) {}

    template<typename TArchive>
    Parent(TArchive& archive)
    {
        archive >> *this;
    }

    template<class TArchive>
    void serialize(TArchive& archive, const unsigned int version)
    {
        archive & mParentData;
    }
};

class Child : public Parent
{
public:

    Child(const double data) : Parent(data) {}

    template<typename TArchive>
    Child(TArchive& archive) : Parent(archive)
    {
        // Do nothing, as the only data to read is in Parent
    }

    template<class TArchive>
    void serialize(TArchive& archive, const unsigned int version)
    {
        // Let the parent do its serialization
        archive & boost::serialization::base_object<Parent>(*this);

        // Nothing else to do, as the only data to read/write is in Parent
    }
};

int main()
{
    Child child(1.2);

    {
        std::ofstream outputStream("test.txt");
        boost::archive::text_oarchive outputArchive(outputStream);

        outputArchive << child;
        outputStream.close();
    }

    {
        std::ifstream inputStream("test.txt");
        boost::archive::text_iarchive inputArchive(inputStream);
        Child childRead(inputArchive);

        std::cout << "childRead:" << std::endl
                  << childRead.mParentData << std::endl; // Outputs 0 (expected 1.2)
    }

    return 0;
}

So the call chain should (and does) look like:

Output:

Child::serialize()
Parent::serialize()

Input:

Child(archive)
Parent(archive)
Parent::serialize()

However, the mParentData ends up as 0 in childRead, when I would expect it to be 1.2.

Can anyone spot the error?

----------- EDIT -----------

As pointed out by @stijn , in the case where the child has no additional data to serialize, we can simply remove the serialize() function from Child entirely, like this:

#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>

#include <fstream>

class Parent
{
public:
    double mParentData;

    Parent(const double data) : mParentData(data) {}

    template<typename TArchive>
    Parent(TArchive& archive)
    {
        archive >> *this;
    }

    template<class TArchive>
    void serialize(TArchive& archive, const unsigned int version)
    {
        archive & mParentData;
    }
};

class Child : public Parent
{
public:

    Child(const double data) : Parent(data) {}

    template<typename TArchive>
    Child(TArchive& archive) : Parent(archive)
    {
        // Do nothing, as the only data to read is in Parent
    }

};

int main()
{
    Child child(1.2);

    {
        std::ofstream outputStream("test.txt");
        boost::archive::text_oarchive outputArchive(outputStream);

        outputArchive << child;
        outputStream.close();
    }

    {
        std::ifstream inputStream("test.txt");
        boost::archive::text_iarchive inputArchive(inputStream);
        Child childRead(inputArchive);

        std::cout << "childRead:" << std::endl
                  << childRead.mParentData << std::endl; // Outputs 0 (expected 1.2)
    }

    return 0;
}

However, in the case when both the child and parent have data to serialize, and they both do not have a default constructor, the pattern seems like it would need to be something like the following, but not quite. In the Child deserializing constructor, we are calling both the Parent deserializing constructor, but also the Child::serialize() function, which calls the Parent::serialize() function, so effectively the Parent would try to deserialize twice. This incorrect behavior is demonstrated here:

#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>

#include <fstream>

class Parent
{
public:
    double mParentData;

    Parent(const double data) : mParentData(data) {}

    template<typename TArchive>
    Parent(TArchive& archive)
    {
        archive >> *this;
    }

    template<class TArchive>
    void serialize(TArchive& archive, const unsigned int version)
    {
        archive & mParentData;
    }
};

class Child : public Parent
{
public:

    double mChildData;

    Child(const double parentData, const double childData) : Parent(parentData), mChildData(childData) {}

    template<typename TArchive>
    Child(TArchive& archive) : Parent(archive)
    {
        archive >> *this;
    }

    template<class TArchive>
    void serialize(TArchive& archive, const unsigned int version)
    {
        // Let the parent do its serialization
        archive & boost::serialization::base_object<Parent>(*this);

        // Do the child serialization
        archive & mChildData;
    }
};

int main()
{
    Child child(1.2, 3.4);

    {
        std::ofstream outputStream("test.txt");
        boost::archive::text_oarchive outputArchive(outputStream);

        outputArchive << child;
        outputStream.close();
    }

    {
        std::ifstream inputStream("test.txt");
        boost::archive::text_iarchive inputArchive(inputStream);
        Child childRead(inputArchive);

        std::cout << "childRead:" << std::endl
                  << childRead.mParentData << std::endl  // Outputs 0.2 (expected 1.2)
                  << childRead.mChildData << std::endl; // Outputs 3.4 correctly
    }

    return 0;
}

It seems like somehow we need to call a different version of Child::serialize() from the Child deserializing constructor? Or set a flag to not explicitly deserialize Parent from Child::serialize() if it is called from the Child deserializing constructor?

If we change the Child::serialize() to the following, I get a segfault:

template<class TArchive>
void serialize(TArchive& archive, const unsigned int version)
{
    // Let the parent do its serialization
    Parent::serialize(archive, version);

    // Do the child serialization
    archive & mChildData;
}

I believe that you don't need to forward the deserialization to the parent. Changing your code to

#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>

#include <fstream>

class Parent
{
public:
  double mParentData;

  Parent(const double data) : mParentData(data) {}

  template<typename TArchive>
  Parent(TArchive& archive, bool deserialize = false)
  {
    if (!deserialize)
      archive >> *this;
  }

  template<class TArchive>
  void serialize(TArchive& archive, const unsigned int version)
  {
    archive & mParentData;
  }
};

class Child : public Parent
{
public:

  Child(const double data) : Parent(data) {}

  template<typename TArchive>
  Child(TArchive& archive) : Parent(archive, true)
  {
    archive >> *this;
  }

  template<class TArchive>
  void serialize(TArchive& archive, const unsigned int version)
  {
    // Let the parent do its serialization
    archive & boost::serialization::base_object<Parent>(*this);

    // Nothing else to do, as the only data to read/write is in Parent
  }
};

int main()
{
  {
    Child child(1.2);
    std::ofstream outputStream("test.txt");
    boost::archive::text_oarchive outputArchive(outputStream);

    outputArchive << child;
    outputStream.close();
  }

  {
    std::ifstream inputStream("test.txt");
    boost::archive::text_iarchive inputArchive(inputStream);
    Child childRead(inputArchive);


    std::cout << "childRead:" << std::endl
      << childRead.mParentData << std::endl; // Outputs 0 (expected 1.2)
  }

  return 0;
}

works for me.