getopt not accepting argument value starting with

问题:

My script has an option o, which should accept argument as value, as below

./script -o '-p 2' ls

but getopt is not allowing, giving an error

Unrecognized option '-p 2'

code snippet:

ARGS=$(getopt -a -n $0 -o o::h -- "$@")
   eval set -- "$ARGS"
   while true
   do
     case "$1" in
      -o) opt="$2"; echo "options: $2"; shift; shift;;
      -h) echo "$usage"; exit 0;;
      --) cmd="$2"; shift; break;;
     esac
   done

How can I pass arguments as value to script?

回答1:

You should use getopts following a tutorial

#!/bin/bash
while getopts "o:h" opt; do
   case $opt in
      o) option="$OPTARG"; echo "options: $option";;
      h) echo "$usage"; exit 0;;
   esac
done
cmd="${@: -1}" # Warning: Get the last argument, even if it doesn't exist !

回答2:

getopt is buggy and obsolete, please try getopts.