It's getting difficult to group and display records every 5 days.
Here is my data:
FLIGHT_DATE LANDINGS PILOTID COPILOTNAME MONT DPT
11/16/2013 1 A B 11 5.5
11/17/2013 1 A B 11 13
11/19/2013 1 A B 11 12.55
11/19/2013 1 A B 11 4
11/21/2013 1 A B 12 6
11/24/2013 1 A B 12 6.03
11/25/2013 1 A B 11 5.5
11/26/2013 1 A B 11 13
11/26/2013 1 A B 11 12.55
11/30/2013 1 A B 11 4
12/1/2013 1 A B 12 6
12/2/2013 1 A B 12 6.03
I want to show it as below:
Week Start Week End DPT
11/17/2013 11/21/2013 35.55
11/22/2013 11/26/2013 37.08
11/27/2013 12/1/2013 6
12/2/2013 12/6/2013 6.03
Here it is my proposed solution:
DECLARE @MinDate AS DATETIME = (SELECT MIN(flight_date) FROM flights);
WITH cte
AS
(
SELECT
flight_date, DATEDIFF(DAY, @MinDate, flight_date) AS NoDays,
DATEDIFF(DAY, @MinDate, flight_date)/5 AS NoGroup,
DPT
FROM flights
)
SELECT
DATEADD(DAY, NoGroup*5, @MinDate) AS [Week Start],
DATEADD(DAY, NoGroup*5+4, @MinDate) AS [Weed End],
SUM(DPT)
FROM cte
GROUP BY NoGroup;
The idea is to form groups of 5 days, then associate a record to a specific group based on division with 5. NoDays represents the days spent from MinDate to Flight_Date.
You can use this query. You need to specify the start date from which you want to count and the number of days in each period (which seems to be 5 in your case) but please adjust those numbers as needed.
declare @startdate date = '20131117'
declare @interval int = 5
select dateadd(dd, @interval * (o.number - 1), @startdate) WeekStart,
dateadd(dd, @interval * o.number - 1, @startdate) WeekEnd,
sum(d.DPT) DPT
from yourtable d
inner join
(select ROW_NUMBER() over (order by object_id) as number from sys.all_objects) as o
on d.FLIGHT_DATE >= dateadd(dd, @interval * (o.number - 1), @startdate)
and d.FLIGHT_DATE < dateadd(dd, @interval * o.number, @startdate)
group by o.number
order by dateadd(dd, @interval * (o.number - 1), @startdate)