PHP: Remove URL Param?

问题:

I have a function that I call with ?clear-cart appended to the end of my page; as you can probably guess, this function clears the user's cart.

I call it like this

<a href="?clear-cart">Clear Cart</a>

Which works great (in that it loads the same page, but now the cart is cleared), except that the URL in the address bar now reads

http://test.local/cart?clear-cart

Is there anyway to call ?clear-cart but have the URL return without the parameter? (Hide it from the user, since I'm only using it for an internal function call??)

回答1:

You could clear the cart and then immediately redirect using header (obviously before any output!).

<?php
    header('Location: http://test.local/cart');
    ... clear the cart ...
?>

See the PHP reference manual for more details.

回答2:

Instead of a GET-request use a POST-request?

回答3:

Something along the lines of this should do what you want:

if (isset($_GET['clear-cart'])) {

  clear_cart();
  header('Location: http://test.local/');

}

Modify to suit your needs.

回答4:

You can write your cart clearing code in another script and have it redirect back to your page when it's done.

回答5:

Well, in the function that clears the cart, you could redirect the user to the correct URL, using the header() function.

回答6:

Have the page http://test.local/cart link to the page http://test.local/cart?clear-cart, which then redirects the user back to http://test.local/cart.

/cart -> /cart?clear-cart -> /cart

if (isset($_GET['clear-cart'])) {
  // Do some cart clearing...
  // Redirect back
  header('Location: /cart');
  exit;   // Very important, otherwise the script will continue until it finally redirects
}