Bash: Why does reading and writing to the same fil

问题:

I have a bunch a files that contain many blank lines, and want to remove any repeated blank lines to make reading the files easier. I wrote the following script:

#!/bin/bash
for file in * ; do cat "$file" | sed 's/^ \+//' | cat -s > "$file" ; done

However, this had very unreliable results, with most files becoming completely empty and only a few files having the intended results. What's more, the files that did work seemed to change randomly every time I retried, as different files would get correctly edited in every run. What's going on?

Note: This is more of a theoretical question, because I realize I could use a workaround like:

#!/bin/bash
for file in * ; do 
    cat "$file" | sed 's/^ \+//' | cat -s > "$file"-tmp
    rm "$file"
    mv "$file"-tmp "$file"
done

But that seems unnecessarily convoluted. So why is the "direct" method so unreliable?

回答1:

The unpredictability happens because there's a race condition between two stages in the pipeline, cat "$file" and cat -s > "$file".

The first tries to open the file and read from it, while the other tries to empty the file.

• If it's emptied before it's read, you get an empty file.
• If it's read before it's emptied, you get some data (but the file is emptied shortly after and the result is truncated unless it's very short).

If you have GNU sed, you can simply do sed -i 'expression' *

回答2:

You cannot read from a file if you are writing to it at the same time. The > redirection first clears the file, so there is nothing more to read.

You can use sed -i -e '/^$/d' to remove empty lines (if your sed supports -i), which creates the temporary file under the hood.