Possible Duplicate:
Problem with PHP ternary operator
I was reading up a bit on PHP in this article, and I stopped for a while to consider one of his gripes. I can't figure out how on earth PHP comes to the result that it does.
Unlike (literally!) every other language with a similar operator, ?: is left associative. So this:
$arg = 'T';
$vehicle = ( ( $arg == 'B' ) ? 'bus' :
( $arg == 'A' ) ? 'airplane' :
( $arg == 'T' ) ? 'train' :
( $arg == 'C' ) ? 'car' :
( $arg == 'H' ) ? 'horse' :
'feet' );
echo $vehicle;
prints horse.
What logical path does PHP follow that results in 'horse'
being assigned to $vehicle
?
Bracketing is the solution for both understanding and fixing:
This should have the unintended result (horse
):
$arg = 'T';
$vehicle = (
(
(
(
(
( $arg == 'B' ) ? 'bus' : ( $arg == 'A' )
) ? 'airplane' : ( $arg == 'T' )
) ? 'train' : ( $arg == 'C' )
) ? 'car' : ( $arg == 'H' )
) ? 'horse' : 'feet'
);
echo $vehicle;
This should have the indended result (train
):
$arg = 'T';
$vehicle = (
( $arg == 'B' ) ? 'bus' : (
( $arg == 'A' ) ? 'airplane' : (
( $arg == 'T' ) ? 'train' : (
( $arg == 'C' ) ? 'car' : (
( $arg == 'H' ) ? 'horse' : 'feet'
)
)
)
)
);
echo $vehicle;
Note:
It is recommended that you avoid "stacking" ternary expressions. PHP's behaviour when using more than one ternary operator within a single statement is non-obvious:
<?php
// on first glance, the following appears to output 'true'
echo (true?'true':false?'t':'f');
// however, the actual output of the above is 't'
// this is because ternary expressions are evaluated from left to right
// the following is a more obvious version of the same code as above
echo ((true ? 'true' : false) ? 't' : 'f');
// here, you can see that the first expression is evaluated to 'true', which
// in turn evaluates to (bool)true, thus returning the true branch of the
// second ternary expression.
?>
http://php.net/manual/en/language.operators.comparison.php#language.operators.comparison.ternary