Passing URL in Codeigniter URL segment

问题:

I want to pass a url like http://example.com/test?a=1&b=2 in url segment of codeigniter.

I'm trying to pass something like this http://myurl.com/abc/http://example.com/test?a=1&b=2 and get the "http://example.com/test?a=1&b=2" url. What should be the best way to do this?

回答1:

Set your URI protocol to REQUEST_URI in application/config/config.php , like this:

$config['uri_protocol'] = 'REQUEST_URI';

then use GET method:

$this->input->get('a');

EDIT:

Since http://example.com/test?a=1&b=2 is not encoded URL, it isn't possible. So first, I would encode URL with urlencode function like this:

urlencode('http://example.com/test?a=1&b=2');

it returns something like: http%3A%2F%2Fexample.com%2Ftest%3Fa%3D1%26b%3D2

So I would pass the URL like this:

http://myurl.com/?url=http%3A%2F%2Fexample.com%2Ftest%3Fa%3D1%26b%3D2

then get an example URL with GET method.

$this->input->get('url');

回答2:

Here is a link to an article that answers this questin - http://wildlyinaccurate.com/segment-based-urls-with-query-strings-in-codeigniter-2/ Remember Google is you best friend.

回答3:

Use this technique to get the URL

$url = "http://example.com/test?a=1&b=2";
$segments = array($controller, $action, $url);
echo site_url($segments);

// or create a anchor link
echo anchor($segments, "click me");

回答4:

Pass urlendode()'d URL in segment and then decode it with own (MY_*) class:

application/core/MY_URI.php:

<?php

class MY_URI extends CI_URI {

    function _filter_uri($str)
    {
        return rawurldecode(parent::_filter_uri($str));
    }
}

// EOF