Question: Is there in 2018 any CSS construct that would hide divs using a selector and then unhide one containing a specific selector?
I was marking this a a dupe
CSS Selector: If a Container is empty -> display: none;
Code would be
div { border: 1px solid black; text-align:center; width:400px }
div[id*="accordion_prop_floor_plans"]:empty { display:none }
<div id="accordion_prop_floor_plans_1"></div>
<div id="accordion_prop_floor_plans_2"><img src="https://via.placeholder.com/350x150&text=image" title="image here" /><br/>Plan 2</div>
<div id="accordion_prop_floor_plans_3"></div>
Then I realised that there might be another use case.
Hide divs that do not have a certain element. Or show divs that do.
I tried :has()
, based on Is there a CSS parent selector?
but it does not work yet in any browser as of 2018
div { border: 1px solid black; text-align:center; width:400px }
div[id*="accordion_prop_floor_plans"] { display:none }
div[id*="accordion_prop_floor_plans"]:has(> img) { display:block }
<div id="accordion_prop_floor_plans_1">Plan 1</div>
<div id="accordion_prop_floor_plans_2"><img src="https://via.placeholder.com/350x150&text=image" title="image here" /><br/>Plan 2</div>
<div id="accordion_prop_floor_plans_3">Plan 3</div>
I can do it in JS easily:
document.querySelector('div[id*="accordion_prop_floor_plans"]>img').parentNode.style.display="block";
div { border: 1px solid black; text-align:center; width:400px }
div[id*="accordion_prop_floor_plans"] { display:none }
<div id="accordion_prop_floor_plans_1">Plan 1</div>
<div id="accordion_prop_floor_plans_2"><img src="https://via.placeholder.com/350x150&text=image" title="image here" /><br/>Plan 2</div>
<div id="accordion_prop_floor_plans_3">Plan 3</div>