问题:

The following is valid Rust:

enum Foo {
    One(i32, i32, i32),
    Two { x: i32, y: i32 },
}

fn main() {
    let x: [Foo; 2] = [Foo::One(1, 2, 3), Foo::Two { x: 1, y: 2 }];
}

How does Rust store this? The first element is 12 bytes while the second one is 8 (plus a tag byte in the beginning I guess). Does it only store references to the elements in the array?

回答1:

All variants of an enum use the same amount of memory (in case of your Foo type, 16 bytes, at least on my machine). The size of the enum's values is determined by its largest variant (One, in your example).

Therefore, the values can be stored in the array directly.

回答2:

Rust being a systems programming language, you can just ask it!

use std::mem;

enum Foo {
    One(i32, i32, i32),
    Two { x: i32, y: i32 },
}

fn main() {
    println!("{}", mem::size_of::<Foo>());
}

This prints 16 on the playground.

And note that I did not specify whether I talked about One or Two, because it does not matter. Foo has a unique size.

As a rule of thumb, you might want to avoid storing a very large variant. One solution, if a single variant is much bigger than the other, is to reach out to Box.