Select / assign to data.table when variable names

问题:

How do you refer to variables in a data.table if the variable names are stored in a character vector? For instance, this works for a data.frame:

df <- data.frame(col1 = 1:3)
colname <- \"col1\"
df[colname] <- 4:6
df
#   col1
# 1    4
# 2    5
# 3    6

How can I perform this same operation for a data.table, either with or without := notation? The obvious thing of dt[ , list(colname)] doesn\'t work (nor did I expect it to).

回答1:

Two ways to programmatically select variable(s):

1. with = FALSE:

   DT = data.table(col1 = 1:3)
   colname = \"col1\"
   DT[, colname, with = FALSE] 
   #    col1
   # 1:    1
   # 2:    2
   # 3:    3
   

2. \'dot dot\' (..) prefix:

   DT[, ..colname]    
   #    col1
   # 1:    1
   # 2:    2
   # 3:    3
   

For further description of the \'dot dot\' (..) notation, see New Features in 1.10.2 (it is currently not described in help text).

To assign to variable(s), wrap the LHS of := in parentheses:

DT[, (colname) := 4:6]    
#    col1
# 1:    4
# 2:    5
# 3:    6

The latter is known as a column plonk, because you replace the whole column vector by reference. If a subset i was present, it would subassign by reference. The parens around (colname) is a shorthand introduced in version v1.9.4 on CRAN Oct 2014. Here is the news item:

Using with = FALSE with := is now deprecated in all cases, given that wrapping the LHS of := with parentheses has been preferred for some time.

colVar = \"col1\"
DT[, colVar := 1, with = FALSE]                 # deprecated, still works silently
DT[, (colVar) := 1]                             # please change to this
DT[, c(\"col1\", \"col2\") := 1]                    # no change
DT[, 2:4 := 1]                                  # no change
DT[, c(\"col1\",\"col2\") := list(sum(a), mean(b)]  # no change
DT[, `:=`(...), by = ...]                       # no change

See also Details section in ?`:=`:

DT[i, (colnamevector) := value]
# [...] The parens are enough to stop the LHS being a symbol

---

And to answer further question in comment, here\'s one way (as usual there are many ways) :

DT[, colname := cumsum(get(colname)), with = FALSE]
#    col1
# 1:    4
# 2:    9
# 3:   15 

or, you might find it easier to read, write and debug just to eval a paste, similar to constructing a dynamic SQL statement to send to a server :

expr = paste0(\"DT[,\",colname,\":=cumsum(\",colname,\")]\")
expr
# [1] \"DT[,col1:=cumsum(col1)]\"

eval(parse(text=expr))
#    col1
# 1:    4
# 2:   13
# 3:   28

If you do that a lot, you can define a helper function EVAL :

EVAL = function(...)eval(parse(text=paste0(...)),envir=parent.frame(2))

EVAL(\"DT[,\",colname,\":=cumsum(\",colname,\")]\")
#    col1
# 1:    4
# 2:   17
# 3:   45

Now that data.table 1.8.2 automatically optimizes j for efficiency, it may be preferable to use the eval method. The get() in j prevents some optimizations, for example.

Or, there is set(). A low overhead, functional form of :=, which would be fine here. See ?set.

set(DT, j = colname, value = cumsum(DT[[colname]]))
DT
#    col1
# 1:    4
# 2:   21
# 3:   66

回答2:

*This is not an answer really, but I don\'t have enough street cred to post comments :/

Anyway, for anyone who might be looking to actually create a new column in a data table with a name stored in a variable, I\'ve got the following to work. I have no clue as to it\'s performance. Any suggestions for improvement? Is it safe to assume a nameless new column will always be given the name V1?

colname <- as.name(\"users\")
# Google Analytics query is run with chosen metric and resulting data is assigned to DT
DT2 <- DT[, sum(eval(colname, .SD)), by = country]
setnames(DT2, \"V1\", as.character(colname))

Notice I can reference it just fine in the sum() but can\'t seem to get it to assign in the same step. BTW, the reason I need to do this is colname will be based on user input in a Shiny app.

回答3:

For multiple columns and a function applied on column values.

When updating the values from a function, the RHS must be a list object, so using a loop on .SD with lapply will do the trick.

The example below converts integer columns to numeric columns

a1 <- data.table(a=1:5, b=6:10, c1=letters[1:5])
sapply(a1, class)  # show classes of columns
#         a           b          c1 
# \"integer\"   \"integer\" \"character\" 

# column name character vector
nm <- c(\"a\", \"b\")

# Convert columns a and b to numeric type
a1[, j = (nm) := lapply(.SD, as.numeric ), .SDcols = nm ]

sapply(a1, class)
#         a           b          c1 
# \"numeric\"   \"numeric\" \"character\"