what is the windows equivalent of the command “dat

I'm writing a batch script and I need the unix time. It's easy under linux, but I can't figure out how to do this in windows.

回答1:

Here is a native batch solution that should work in any locale. It uses WMIC to get the current local time in a locale independent manner. Everything else is a "simple" matter of string parsing and basic math.

:UnixTime  [ReturnVar]  [TimeStamp]
::
:: Computes the Unix time from the current local time as reported by the
:: operating system. The Unix time is the number of seconds that have elapsed
:: since midnight Coordinated Universal Time (UTC), January 1, 1970, not
:: counting leap seconds.
::
:: The result is returned in variable ReturnVar,
:: or the result is echoed if ReturnVar is not specified
::
:: If the TimeStamp is provided in the 2nd parameter, then the Unix time for
:: the TimeStamp is computed, rather then for the current time.
::
:: The TimeStamp must have the same format as used by WMIC:
::
::   YYYYMMDDhhmmss.ffffffSzzz
::
:: where:
::
::   YYYY   = gregorian year
::   MM     = month
::   DD     = day
::   hh     = hour in 24 hour format
::   mm     = minute
::   ss     = seconds
::   ffffff = fractional seconds (microseconds)
::   S      = timezone sign: + or -
::   zzz    = timezone: minutes difference from GMT
::
:: Each component must be zero prefixed as needed to maintain the proper width.
::
:: The ReturnVar parameter must be provided in order to use the TimeStamp.
:: A ReturnVar of "" will function the same as no ReturnVar. This enables the
:: specification of a TimeStamp without an actual ReturnVar.
::
@echo off
setlocal
set "ts=%~2"
if not defined ts for /f "skip=1 delims=" %%A in ('wmic os get localdatetime') do if not defined ts set "ts=%%A"
set /a "yy=10000%ts:~0,4% %% 10000, mm=100%ts:~4,2% %% 100, dd=100%ts:~6,2% %% 100"
set /a "dd=dd-2472663+1461*(yy+4800+(mm-14)/12)/4+367*(mm-2-(mm-14)/12*12)/12-3*((yy+4900+(mm-14)/12)/100)/4"
set /a ss=(((1%ts:~8,2%*60)+1%ts:~10,2%)*60)+1%ts:~12,2%-366100-%ts:~21,1%((1%ts:~22,3%*60)-60000)
set /a ss+=dd*86400
endlocal & if "%~1" neq "" (set %~1=%ss%) else echo %ss%
exit /b

Note that this solution has a limited life span. It will cease to work on 2038-01-19 when the Unix time exceeds the maximum value of a signed 32 bit integer.

EDIT - The code has been edited to support conversion of a timestamp string on the command line instead of the current local time. The precise range of times supported is 1901-12-13 20:45:52.000000 through 2038-01-19 03:14:07.999999 GMT. Times prior to 1970-01-01 00:00:00.000000 will yield negative values.

回答2:

If by "unix time" you mean the epoch second, then Windows doesn't include tools to produce that. Instead, you can install third-party tools. For example:

Install Cygwin.
Find the date binary (under C:\Cygwin\ or wherever you installed it)
Use it as you would in Linux.

Alternately, per the awesome comment on this answer, you could install GNU Coreutils which also include a date command. It includes a number of other tools that you may not need, but then, so does Cygwin.

回答3:

You can use vbscript in windows, the interpreter is available on your system.

'--------------------epoch.vbs----------------------- 
option explicit
dim s,o,z
for each o in GetObject("winmgmts:").InstancesOf ("Win32_OperatingSystem")
z=o.CurrentTimeZone
next
s=DateDiff("s", "01/01/1970 00:00:00", Now())-(60*z)
wscript.echo(s)
wscript.quit