I try to find name of previous route in Laravel 5.1.
With:
{!! URL::previous() !!}
I get the route url, but I try to get route name like I get for current page:
{!! Route::current()->getName() !!}
My client wont a different text for Thank you page, depends on from page (Register page or Contact page) user go to Thank you page. I try with:
{!! Route::previous()->getName() !!}
But that didn't work. I try to get something like:
@if(previous-route == 'contact')
some text
@else
other text
@endif
Here what work for me. I find this answer and this question and modify it to work in my case: https://stackoverflow.com/a/36476224/2807381
@if(app('router')->getRoutes()->match(app('request')->create(URL::previous()))->getName() == 'public.contact')
Some text
@endif
You can't get route name of previous page, so your options are:
Check previous URL instead of a route name.
Use sessions. First, save route name:
session()->flash('previous-route', Route::current()->getName());
Then check if session has previous-route
:
@if (session()->has(`previous-route`) && session(`previous-route`) == 'contacts')
Display something
@endif
- Use
GET
parameters to pass route name.
If I were you, I'd use sessions or would check previous URL.
I've created a helper function like this.
/**
* Return whether previous route name is equal to a given route name.
*
* @param string $routeName
* @return boolean
*/
function is_previous_route(string $routeName) : bool
{
$previousRequest = app('request')->create(URL::previous());
try {
$previousRouteName = app('router')->getRoutes()->match($previousRequest)->getName();
} catch (\Symfony\Component\HttpKernel\Exception\NotFoundHttpException $exception) {
// Exception is thrown if no mathing route found.
// This will happen for example when comming from outside of this app.
return false;
}
return $previousRouteName === $routeName;
}