PHP: increment counter function using words (i.e.

问题:

I've been trying to find a function which increments a counter using words. I know its possible using numbers with suffixes (i.e. 1st, 2nd, 3rd and so on). Here is a snippet of the code i've got:

function addOrdinalNumberSuffix($num) {
    if (!in_array(($num % 100),array(11,12,13))){
        switch ($num % 10) {
            // Handle 1st, 2nd, 3rd
            case 1:  return $num.'st';
            case 2:  return $num.'nd';
            case 3:  return $num.'rd';
        }
    }
    return $num.'th';
}

Code Source

But is there a way to replicate this with words (i.e First, Second, Third, etc..)?

I'd expect it to be quite difficult (but not impossible) to create an infinite counter, but anything up to 20 would suffice.

Any help would be much appreciated.

回答1:

There is a class from PEAR package can do that:

<?php

// include class
include("Numbers/Words.php");

// create object
$nw = new Numbers_Words();

// convert to string
echo "600 in words is " . $nw->toWords(600);

?>

Source.

回答2:

Twenty isn't that much to hardcode. You'd just need an array, not a function.

$array = array('First', 'Second', 'Third', ...);

foreach ($array as $key => $value)
{
  echo "$value index is $key";
}

The more direct answer is: There isn't a built in function that does what you're looking for.

回答3:

Here goes some pseudo code to perhaps lead on a hopefully good way:

input = //any number
output = string (input)
if output ends with '1' then output += 'st'
else if output ends with '2' then output += 'nd'
else if output ends with '3' then output += 'rd'
else output += 'th'

回答4:

<?php

    /*****************************************************************************/

function ToOrdinal($n) {
  /* Convert a cardinal number in the range 0 - 999 to an ordinal in
     words. */

  /* The ordinal will be collected in the variable $ordinal.
   Initialize it as an empty string.*/
  $ordinal = "";

  /* Check that the number is in the permitted range. */
  if ($n >= 0 && $n <= 999)
    null;
  else{
    echo "<br />You have called the function ToOrdinal with this value: $n, but
it is not in the permitted range, from 0 to 999, inclusive.<br />";
    return;
  }
  /* Extract the units. */
  $u = $n % 10;

  /* Extract the tens. */
  $t = floor(($n / 10) % 10);

  /* Extract the hundreds. */
  $h = floor($n / 100);

  /* Determine the hundreds */
  if ($h > 0) {

    /* ToCardinalUnits() works with numbers from 0 to 9, so it's okay
       for finding the number of hundreds, which must lie within this
       range. */
    $ordinal .= ToCardinalUnits($h);
    $ordinal .= " hundred";

    /* If tens and units are zero, append "th" and quit */
    if ($t == 0 && $u == 0) {
      $ordinal .=  "th";
    } else {
      /* Otherwise put in a blank space to separate the hundreds from
     what follows. */
      $ordinal .= " ";
    }
  }

  /* Determine the tens, unless there is just one ten.  If units are 0,
     handle them separately */
  if ($t >= 2 && $u != 0) {
    switch ($t) {
    case 2:
      $ordinal .= "twenty-";
      break;
   case 3:
      $ordinal .= "thirty-";
      break;
    case 4:
      $ordinal .= "forty-";
      break;
    case 5:
      $ordinal .= "fifty-";
      break;
    case 6:
      $ordinal .= "sixty-";
      break;
    case 7:
      $ordinal .= "seventy-";
      break;
    case 8:
      $ordinal .= "eighty-";
      break;
    case 9:
      $ordinal .= "ninety-";
      break;
    }
  }
  /* Print the tens (unless there is just one ten) with units == 0 */
  if ($t >= 2 && $u == 0) {
    switch ($t) {
    case 2:
      $ordinal .= "twentieth";
      break;
    case 3:
      $ordinal .= "thirtieth";
      break;
    case 4:
      $ordinal .= "fortieth";
      break;
    case 5:
      $ordinal .= "fiftieth";
      break;
    case 6:
      $ordinal .= "sixtieth";
      break;
    case 7:
      $ordinal .= "seventieth";
      break;
    case 8:
      $ordinal .= "eightieth";
      break;
    case 9:
      $ordinal .= "ninetieth";
      break;
    }
  }


  /* Print the teens, if the tens is 1. */
  if ($t == 1) {
    switch ($u) {
    case 0:
      $ordinal .= "tenth";
      break;
    case 1:
      $ordinal .= "eleventh";
      break;
    case 2:
      $ordinal .= "twelfth";
      break;
    case 3:
      $ordinal .= "thirteenth";
      break;
    case 4:
      $ordinal .= "fourteenth";
      break;
    case 5:
      $ordinal .= "fifteenth";
      break;
    case 6:
      $ordinal .= "sixteenth";
      break;
    case 7:
      $ordinal .= "seventeenth";
      break;
    case 8:
      $ordinal .= "eighteenth";
      break;
    case 9:
      $ordinal .= "nineteenth";
      break;
    }
  }

  /* Print the units. */
  if ($t != 1) {
    switch ($u) {
    case 0:
      if ($n == 0)
    $ordinal .= "zeroth";
      break;
    case 1:
      $ordinal .= "first";
      break;
    case 2:
      $ordinal .= "second";
      break;
    case 3:
      $ordinal .= "third";
      break;
    case 4:
      $ordinal .= "fourth";
      break;
    case 5:
      $ordinal .= "fifth";
      break;
    case 6:
      $ordinal .= "sixth";
      break;
    case 7:
      $ordinal .= "seventh";
      break;
    case 8:
      $ordinal .= "eighth";
      break;
    case 9:
      $ordinal .= "ninth";
      break;
    }
  }
  return $ordinal;
}

/*****************************************************************************/


function ToCardinalUnits($n) {
  /* Convert a number in the range 0 to 9 into its word equivalent. */

  /* Make sure the number is in the permitted range. */
  if ($n >= 0 && $n <= 9)
    null;
  else
    {
      echo "<br />You have called ToCardinal() with an argument $n, but the permitted range is 0 to 9, inclusive.<br />";
    }

  switch ($n) {
  case 0:
    return "zero";
  case 1:
    return "one";
  case 2:
    return "two";
  case 3:
    return "three";
  case 4:
    return "four";
  case 5:
    return "five";
  case 6:
    return "six";
  case 7:
    return "seven";
  case 8:
    return "eight";
  case 9:
    return "nine";
  }
}



?>

回答5:

Ordinals (English only), based on SIFE's answer:

include("Numbers/Words.php");

function Nth($n)
{
    $nw = new Numbers_Words();
    $s = $nw->toWords($n);
    $replacements = array(
        'one' => 'first',
        'two' => 'second',
        'three' => 'third',
        've' => 'fth',
        't' => 'th',
        'e' => 'th',
        'y' => 'ieth',
        '' => 'th',
    );
    foreach ($replacements as $from => $to)
    {
        $count = 0;
        $r = preg_replace('/' . $from . '$/', $to, $s, 1, $count);
        if ($count)
            return $r;
    }
}

回答6:

Here's a link to a simple PHP function that shows how to handle this in a simple manner: http://webdeveloperblog.tiredmachine.com/php-converting-an-integer-123-to-ordinal-word-firstsecondthird/

The provided example only works into the fifties, but can easily be expanded upon to reach higher ranges.

function numToOrdinalWord($num)
{
    $first_word = array('eth','First','Second','Third','Fouth','Fifth','Sixth','Seventh','Eighth','Ninth','Tenth','Elevents','Twelfth','Thirteenth','Fourteenth','Fifteenth','Sixteenth','Seventeenth','Eighteenth','Nineteenth','Twentieth');
    $second_word =array('','','Twenty','Thirthy','Forty','Fifty');

    if($num <= 20)
        return $first_word[$num];

    $first_num = substr($num,-1,1);
    $second_num = substr($num,-2,1);

    return $string = str_replace('y-eth','ieth',$second_word[$second_num].'-'.$first_word[$first_num]);
}