c# check for a poker straight

问题:

I am trying to write a poker hand evaluation method in c#. I have managed to do this for every poker hand using linq except a straight. For those that don't play a straight is made up of 5 cards with increments of 1 for each card. Ace can be high or low.

I have created an object called card which has a suit, rank and value (J = 11, Q =12 etc..). My method will be passed a list of this object containing 7 cards (hole cards and the board.)

Another thing to bear in mind is that a straight can only be made if the player has a 5 or 10.

See below my methods for other poker hands and please let me know if you have an idea for the straight method. Pseudo code would be fine also.

---

public bool CheckPair(List<Card> cards)
{
    //see if exactly 2 cards card the same rank.
    return cards.GroupBy(card => card.Rank).Count(group => group.Count() == 2) == 1;
}

public bool CheckTwoPair(List<Card> cards)
{
    //see if there are 2 lots of exactly 2 cards card the same rank.
    return cards.GroupBy(card => card.Rank).Count(group => group.Count() >= 2) == 2;
}

public bool CheckTrips(List<Card> cards)
{
    //see if exactly 3 cards card the same rank.
    return cards.GroupBy(card => card.Rank).Any(group => group.Count() == 3);
}
public bool CheckStraight(List<Card> cards)
{
    // order by decending to see order
    var cardsInOrder = cards.OrderByDescending(a => a.Value).ToList();
    // check for ace as can be high and low
    if (cardsInOrder.First().Rank == "A")
    {
        // check if straight with ace has has 2 values
        bool highStraight = cards.Where(a => a.Rank == "K" || a.Rank == "Q" || a.Rank == "J" || a.Rank == "10").Count() == 4;
        bool lowStraight = cards.Where(a => a.Rank == "2" || a.Rank == "3" || a.Rank == "4" || a.Rank == "5").Count() == 4;
        // return true if straight with ace
        if (lowStraight == true || highStraight == true)
        {
            return true;
        }
    }
    else
    {
        // check for straight here
        return true;
    }
    // no straight if reached here.
    return false;

}

public bool CheckFlush(List<Card> cards)
{
    //see if 5 or more cards card the same rank.
    return cards.GroupBy(card => card.Suit).Count(group => group.Count() >= 5) == 1;
}

public bool CheckFullHouse(List<Card> cards)
{
    // check if trips and pair is true
    return CheckPair(cards) && CheckTrips(cards);
}
public bool CheckQuads(List<Card> cards)
{
    //see if exactly 4 cards card the same rank.
    return cards.GroupBy(card => card.Rank).Any(group => group.Count() == 4);
}

// need to check same 5 cards
public bool CheckStraightFlush(List<Card> cards)
{
    // check if flush and straight are true.
    return CheckFlush(cards) && CheckStraight(cards);
}

回答1:

This might not be the best performing check, but I'd say it's very readable which is usually a good property.

Just grab 5 cards, skipping cards you've already seen every iteration and check for a straight for each sequence. An ordered sequence is a straight if it does not contain doubles and if the first and last cards difference is 5.

public bool CheckStraight(List<Card> cards)
{
     //maybe check 5 and 10 here first for performance

     var ordered = cards.OrderByDescending(a => a.Value).ToList();
     for(i = 0; i < ordered.Count - 5; i++) {
          var skipped = ordered.Skip(i);
          var possibleStraight = skipped.Take(5);
          if(IsStraight(possibleStraight)) {
               return true;
          }
     }
     return false;
}

public bool IsStraight(List<Card> fiveOrderedCards) {
     var doubles = cards.GroupBy(card => card.Rank).Count(group => group.Count() > 1);
     var inARow = cards[4] - cards[0] = 5; //Ace is 0

     return !doubles && inARow;
}

回答2:

I have made some small changes to Glubus answer. The code below does the job however you will have to check manually for a wheel (A,1,2,3,4,5) straight.

public bool CheckStraight(List<Card> cards)
    {
        //maybe check 5 and 10 here first for performance

        var ordered = cards.OrderByDescending(a => a.Value).ToList();
        for (var i = 0; i < ordered.Count - 4; i++)
        {
            var skipped = ordered.Skip(i);
            var possibleStraight = skipped.Take(5).ToList();
            if (IsStraight(possibleStraight))
            {
                return true;
            }
        }
        return false;
    }
public bool IsStraight(List<Card> cards)
{
    return cards.GroupBy(card => card.Value).Count() == cards.Count() && cards.Max(card => (int)card.Value) - cards.Min(card => (int)card.Value) == 4;
    }

回答3:

erm,

function bool IsStraight(IEnumerable<int> cards)
{
    var orderedCards = cards.OrderBy(n => n).ToList();
    var test = orderdCards.Zip(orderdCards.Skip(1), (a, b) => b - a);

    var count = 0;
    foreach(var n in test)
    {
        if (n == 1)
        {
            count++;
            if (count == 4)
            {
                return true;
            }
        }
        else
        {
            count = 0;
        }
    }

    return false;
}

回答4:

I cannot think about real one liner, since A can be 1 or 14, but this should be good:

int c = 5; // How many cards straight
bool Ais1 = cards.OrderBy(a => a.Value).Select((i,j) => i.Value-j).Distinct().Skip(1).Count() <= (cards.Count - c);
bool Ais14 = cards.OrderBy(a => (a.Value == 1 ? 14 : a.Value)).Select((i,j) => (i.Value == 1 ? 14 : i.Value)-j).Distinct().Skip(1).Count() <= (cards.Count - c);
return Ais1 || Ais14;

(Updated - thank you Janne, I've fixed the code)