How to swap elements of array?

I want to swap elements of slice data using library function, but it doesn't work because of multiple borrowing:

mem::swap(&mut data[i], &mut data[j]); //error

It could be done manually, as usual:

let temp = data[i];
data[i] = data[j];
data[j] = temp;

but I don't think using this code every time is great. Is there any other solution to use library swap for slices normally?

There's a swap method on slices: data.swap(i, j).

The original code doesn't work because the language requires that &muts do not alias, that is, if a piece of data is accessible via an &mut, then there must be no other way to use that data. In general, for successive indexes data[i], data[j], the compiler cannot guarantee that i and j are different. If they are the same then the indexing is referring to the same memory and so &mut data[i] and &mut data[j] would be two pointers to the same data: illegal!

.swap uses a bit of unsafe code internally, being sure to handle the i == j case correctly, avoiding aliasing &mut pointers. That said, it doesn't have to use unsafe, it is only to ensure this "primitive" operation has high-performance (and I could definitely imagine future language/library improvements that reduce the need for unsafe here by making the require invariants easier to express), e.g. the following is a safe implementation:

use std::cmp::Ordering;
use std::mem;

fn swap<T>(x: &mut [T], i: usize, j: usize) {
    let (lo, hi) = match i.cmp(&j) {
        // no swapping necessary
        Ordering::Equal => return,

        // get the smallest and largest of the two indices
        Ordering::Less => (i, j),
        Ordering::Greater => (j, i),
    };

    let (init, tail) = x.split_at_mut(hi);
    mem::swap(&mut init[lo], &mut tail[0]);
}

The key here is split_at_mut which separates the slice into two disjoint halves (this is done using unsafe internally, but Rust's standard library is built on unsafe: the language provides "primitive" features and the libraries build the rest on top of them).