Exmaple:
[empid date bookid]
----------
1 5/6/2004 8
2 5/6/2004 8
1 5/7/2004 8
1 5/8/2004 6
3 5/8/2004 8
2 5/8/2004 7
In this table,I need to get empid 1 as output..since it has bookid 8 more than once..
thanks in advance..
You can use:
SELECT DISTINCT id
FROM table
GROUP BY empid, bookid
HAVING COUNT(*) > 1
But it will give you duplicates. If, for example, you have 1-8,1-8,1-9,1-9 you will get 1,1 as output because empid 1 has duplicate bookid's for two distinct bookid values. You will need to use SELECT DISTINCT
to filter out the duplicate empid.
SELECT empid
from table
group by empid
having Count(distinct bookid) > 1