Mongo find documents where array contains x values

2019-02-20 19:55发布

问题:

I have a collection which has documents like that one. The entity field is not set in each document and has different values:

{
    "_id" : ObjectId("5388cfbdec82ba7cd5438635"),
    "name" : "Name1",
    "entity" : [ 
        "Entity1", 
        "Entity2", 
        "Entity4",
        "Entity5"
    ]
}

Now I want to find all documents which contains exactly x values of the given array : ["Entity1","Entity2","Entity3","Entity4"]

Expected result

For the document posted above the values Entity1, Entity2, Entity4 are matching:

  • x = 4 the document should not be found (3 matching values but x is 4)
  • x = 3 document should be found (3 matching -> size = x)
  • x = 2 the document should not be found (3 matching values but x is 2)
  • x = 1 the document should not be found (3 matching values but x is 1)

回答1:

You can use aggregation for this. This is probably what you're looking for:

var y = ["Entity1", "Entity2", "Entity3, "Entity4"];
db.coll.aggregate([
    {
        $project :
        {
            _id : 1,
            name : 1,
            entity : 1,
            x : {
                $size : {
                    $ifNull: [{$setIntersection : ["$entity", y]}, []]
                }
            }
        } 
    },
    { $match : { x : 3 } }
]);


标签: mongodb nosql