Convert(decode) hex string to ASCII or any other u

问题:

b'7668647866696c654d006900630072006f0073006f00660074002000570069006e0064006f0077007300200036002e0033002e0039003600300030002e003100370033003900360000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000'

I want to convert this hex string to ascii or readable text. I am getting this block from a system image file.

回答1:

Expanding on Joran's answer,

import string
data = bytes.fromhex(b'7668647866696c654d006900630072006f0073006f00660074002000570069006e0064006f0077007300200036002e0033002e0039003600300030002e003100370033003900360000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000'.decode("ascii"))
print("".join(chr(c) if chr(c) in string.printable else '.' for c in data))

Result:

vhdxfileM.i.c.r.o.s.o.f.t. .W.i.n.d.o.w.s. .6...3...9.6.0.0...1.7.3.9.6.........................................................................................................................................................................................

Note that this won't give you a perfect lossless representation of the data - unreadable characters get replaced with periods. So it's only really suitable if you're searching for textual data.

回答2:

'7668647866696c654d006900630072006f0073006f00660074002000570069006e0064006f0077007300200036002e0033002e0039003600300030002e003100370033003900360000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000'.decode("hex")

at least in py2x

in 3x

bytes.fromhex(b'7668647866696c654d006900630072006f0073006f00660074002000570069006e0064006f0077007300200036002e0033002e0039003600300030002e003100370033003900360000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000'.decode("ascii"))