Replacing tel or telprompt to call

2019-02-20 13:21发布

问题:

I've made an application is used to call predefined numbers upon button press. As far as i know the only way to make call inside app is to use "tel" or "telprompt". When i submitted an app i've received a rejection with this description:

2.5 Details

Your app uses or references the following non-public APIs, which is a violation of the App Store Review Guidelines:

teleprompt://

The use of non-public APIs is not permitted in the App Store because it can lead to a poor user experience should these APIs change.

For my first submission I used "telprompt" to call, then I changed it to "tel" because i read here that many apps were accepted with it and after second submission i received the same response with rejection. Can someone advice m how to use dial functions in app without "tel" or "telprompt"? Any help is appreciated, thanks!

upd: added text for second rejection

Hello,

Thank you for your resubmission. We noticed that your app still uses or references the teleprompt:// API, which is in violation of the App Store Review Guidelines.

We are unable to proceed with the review of your app until this issue has been addressed.

回答1:

From your update, it suggests you're sending tel://... or teleprompt://... as a URL. The tel: scheme takes a series of digits. / is not a digit, so there's no reason you should be passing that as part of the number.



回答2:

Use following code:

NSString *phoneNumber = @"+91 2308966";
NSString *phoneURLString = [NSString stringWithFormat:@"tel:%@", phoneNumber];
NSURL *phoneURL = [NSURL URLWithString:phoneURLString];
[[UIApplication sharedApplication] openURL:phoneURL];

This code is working for an app which I submitted to the Appstore.



回答3:

You have used telEprompt:// instead of telprompt://