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问题:
I've been researching a bit and I found that CakePHP's form helper doesn't interpret ENUM fields correctly, so it simply outputs a text input. I found a post that suggested to use a helper for that specific purpose. Does anybody know a better way to achieve this? Or if CakePHP devs intend to correct this some day?
Thanks for reading!
回答1:
Below is one of the helper extention.
App::uses('FormHelper', 'View/Helper');
/**
* APP/View/Helper/MySqlEnumFormHelper.php
* It extends FormHelper to implement ENUM datatype of MySQL.
*
* http://blog.xao.jp/blog/cakephp/implementation-of-mysql-enum-datatype-in-formhelper/
*
* created Oct. 15, 2012
* CakePHP 2.2.3
*/
class MySqlEnumFormHelper extends FormHelper
{
public function input($fieldName, $options = array())
{
if (!isset($options['type']) && !isset($options['options'])) {
$modelKey = $this->model();
if (preg_match(
'/^enum\((.+)\)$/ui',
$this->fieldset[$modelKey]['fields'][$fieldName]['type'],
$m
)) {
$match = trim($m[1]);
$qOpen = substr($match, 0, 1);
$qClose = substr($match, -1);
$delimiter = $qOpen . ',' . $qClose;
preg_match('/^'.$qOpen.'(.+)'.$qClose.'$/u', $match, $m);
$_options = explode($delimiter, $m[1]);
$options['type'] = 'select';
$options['options'] = array_combine($_options, $_options);
}
}
return parent::input($fieldName, $options);
}
}
回答2:
Cake attempts to be database agnostic and therefore this issue won't be "corrected" since it's not a bug. For example, SQL server doesn't have an exact equivalent of MySQL's ENUM field type.
I would recommend getting your possible list of enum values like so:
YourController.php
// get column type
$type = $this->Model->getColumnType('field');
// extract values in single quotes separated by comma
preg_match_all("/'(.*?)'/", $type, $enums);
// enums
var_dump($enums[1]);
Then use a select
field in your view and pass the enums as options. Your current value you'll already have. How does that sound?
回答3:
I am new to cakephp I found some old code and pieced together an enum select box for you enjoy
/**
* Behavior with useful functionality around models containing an enum type field
*
* Copyright (c) Debuggable, http://debuggable.com
*
*
*
* @package default
* @access public
*
* reworked by Nathanael Mallow for cakephp 2.0
*
*/
/*
*Use case:Add this (EnumerableBehavior.php) to app/Model/Behavior/
* -->in the Model add public $actsAs = array('Enumerable');
* -->in the *_controller add $enumOptions = $this->Categorie->enumOptions('Section');
* -->in the view add print $this->Form->input('{db_field_name}', array('options' => $enumOptions, 'label' => 'here'));
*
*
*/
class EnumerableBehavior extends ModelBehavior {
/**
* Fetches the enum type options for a specific field
*
* @param string $field
* @return void
* @access public
*/
function enumOptions($model, $field) {
//Cache::clear();
$cacheKey = $model->alias . '_' . $field . '_enum_options';
$options = Cache::read($cacheKey);
if (!$options) {
$sql = "SHOW COLUMNS FROM `{$model->useTable}` LIKE '{$field}'";
$enumData = $model->query($sql);
$options = false;
if (!empty($enumData)) {
$enumData = preg_replace("/(enum|set)\('(.+?)'\)/", '\\2', $enumData[0]['COLUMNS']['Type']);
$options = explode("','", $enumData);
}
Cache::write($cacheKey, $options);
}
return $options;
}
}
?>
回答4:
If you want to use MySqlEnumFormHelper
instead of normal and call it by $this->Form->
instead by $this->MySqlEnumFormHelper
. You should add this line in your controller to alias MySqlEnumFormHelper
as Form
.
public $helpers = array('Form' => array(
'className' => 'MySqlEnumForm'
));
回答5:
/* comments about previus answers ***
- Use case:Add this (EnumerableBehavior.php) to app/Model/Behavior/
- -->in the Model add public $actsAs = array('Enumerable');
- -->in the action of the *_controller add $enumOptions = $this->YourModelName->enumOptions('db_field_name'); $this->set('enumOptions',$enumOptions);
- -->in the view add print $this->Form->input('{db_field_name}', array('options' => $enumOptions, 'label' => 'here'));
*
*/
回答6:
i think the Behaviour way it's good...but the array keys are integer
so i have modified the function like this
function enumOptions($model, $field) {
//Cache::clear();
$cacheKey = $model->alias . '_' . $field . '_enum_options';
$options = Cache::read($cacheKey);
$enumOptions = array();
if (!$options) {
$sql = "SHOW COLUMNS FROM `{$model->useTable}` LIKE '{$field}'";
$enumData = $model->query($sql);
$options = false;
if (!empty($enumData)) {
$enumData = preg_replace("/(enum|set)\('(.+?)'\)/", '\\2', $enumData[0]['COLUMNS']['Type']);
$options = explode("','", $enumData);
foreach ($options as $option) {
$enumOptions["$option"] = $option;
}
}
Cache::write($cacheKey, $enumOptions);
}
return $enumOptions;
}
in order to be able to save the right value in the db field when the form is submitted
回答7:
I created a function that goes into AppController to handle this. I combined some of the information provided above.
Usage:
$enumList = getEnumValues($ModelField) where ModelField is in this format: 'Model.Field'
Function that I put in AppController:
function getEnumValues($ModelField){
// split input into Model and Fieldname
$m = explode('.', $ModelField);
if ($m[0] == $ModelField) {
return false;
} else {
(! ClassRegistry::isKeySet($m[0])) ? $this->loadModel($m[0]): false;
$type = $this->$m[0]->getColumnType($m[1]);
preg_match_all("/'(.*?)'/", $type, $enums);
foreach ($enums[1] as $value){$enumList[$value] = $value;}
return $enumList;
}
}