search and replace WHOLE WORDS ONLY

I'm looking for a way to search and replace WHOLE WORDS ONLY. Since the whole words in my case can be separated not only by a space but .,;:/? etc. I can't think of an efficient way to code this.

Basically, I'm looking to do something like this

replace([address], ***--list of separators, like .,;:/?--*** & [replacewhat] & ***--list of separators, like .,;:/?--*** ," " & [replacewith] & " ")

I don't know how to pass a list of separators at once instead running a replace function once for each COMBINATION of separators (which combined with 300 words I'm replacing would amount to an insane number of queries)

You can do a replacement with a regular expression using a pattern with the \b marker (for the word boundary) before and after the word you want to replace.

Public Function RegExpReplaceWord(ByVal strSource As String, _
    ByVal strFind As String, _
    ByVal strReplace As String) As String
' Purpose   : replace [strFind] with [strReplace] in [strSource]
' Comment   : [strFind] can be plain text or a regexp pattern;
'             all occurences of [strFind] are replaced
    ' early binding requires reference to Microsoft VBScript
    ' Regular Expressions:
    'Dim re As RegExp
    'Set re = New RegExp
    ' with late binding, no reference needed:
    Dim re As Object
    Set re = CreateObject("VBScript.RegExp")

    re.Global = True
    're.IgnoreCase = True ' <-- case insensitve
    re.pattern = "\b" & strFind & "\b"
    RegExpReplaceWord = re.Replace(strSource, strReplace)
    Set re = Nothing
End Function

As written, the search is case sensitive. If you want case insensitive, enable this line:

re.IgnoreCase = True

In the Immediate window ...

? RegExpReplaceWord("one too three", "too", "two")
one two three
? RegExpReplaceWord("one tool three", "too", "two")
one tool three
? RegExpReplaceWord("one too() three", "too", "two")
one two() three
? RegExpReplaceWord("one too three", "to", "two")
one too three
? RegExpReplaceWord("one too three", "t..", "two")
one two three

... and for your range of delimiters ...

? RegExpReplaceWord("one.too.three", "too", "two")
one.two.three
? RegExpReplaceWord("one,too,three", "too", "two")
one,two,three
? RegExpReplaceWord("one;too;three", "too", "two")
one;two;three
? RegExpReplaceWord("one:too:three", "too", "two")
one:two:three
? RegExpReplaceWord("one/too/three", "too", "two")
one/two/three
? RegExpReplaceWord("one?too?three", "too", "two")
one?two?three
? RegExpReplaceWord("one--too--three", "too", "two")
one--two--three
? RegExpReplaceWord("one***too***three", "too", "two")
one***two***three