Python “regex” module: Fuzziness value

问题:

I'm using the "fuzzy match" functionality of the Regex module.

How can I get the "fuzziness value" of a "match" which indicates how different the pattern is to the string, just like the "edit distance" in Levenshtein?

I thought I could get the value in the Match object, but it's not there. The official docs said nothing about it, neither.

e.g.:

regex.match('(?:foo){e}','for')

a.captures() tells me that the word "for" is matched, but I'd like to know the fuzziness value, which should be 1 in this case.

Is there any way to achieve that?

回答1:

>>> import difflib
>>> matcher = difflib.SequenceMatcher(None, 'foo', 'for')
>>> sum(size for start, end, size in matcher.get_matching_blocks())
2
>>> max(map(len, ('foo', 'for'))) - _
1
>>>
>>>
>>> matcher = difflib.SequenceMatcher(None, 'foo', 'food')
>>> sum(size for start, end, size in matcher.get_matching_blocks())
3
>>> max(map(len, ('foo', 'food'))) - _
1

http://docs.python.org/2/library/difflib.html#difflib.SequenceMatcher.get_matching_blocks http://docs.python.org/2/library/difflib.html#difflib.SequenceMatcher.get_opcodes

回答2:

a = regex.match('(?:foo){e}','for')
a.fuzzy_counts 

this returns a tuple (x,y,z) where:

x = number of substitutions

y = number of insertions and

z = number of deletions

But this is not always a reliable count, ie: the regex match fuzziness night not equate to the true Levinstein distance in some cases

Python regex module fuzzy match: substitution count not as expected