Edit: Title changed, as @Gunner pointed out that this is not a buffer overflow.
In reading user input from stdin
with NR_read
in Linux 64-bit Intel assembly, I wonder how can I avoid that the input that does not fit in the input buffer being sent to Linux shell eg. bash? For example in this example program I have defined an input buffer of 255 bytes (the size of the buffer can be whatever >= 1). The rest of an input longer than 255 bytes is sent to bash (if running from bash) and and this is obviously a serious vulnerability. How should input be read in Linux 64-bit assembly to avoid this vulnerability?
Here's my code:
[bits 64]
section .text
global _start
; can be compiled eg. with nasm or yasm.
; nasm:
; nasm -f elf64 read_stdin_64.asm; ld read_stdin_64.o -o read_stdin_64
; yasm:
; yasm -f elf64 -m amd64 read_stdin_64.asm -o read_stdin_64.o; ld read_stdin_64.o -o read_stdin_64
NR_read equ 0
NR_exit equ 60
STDIN equ 1
; input:
; rax number of syscall
; rdi parameter 1
; rsi parameter 2
; rdx parameter 3
; r10 parameter 4
; r8 parameter 5
; r9 parameter 6
;
; output:
; rax syscall's output
@do_syscall:
push rcx
push r11
syscall ; 64-bit syscall, overwrites rcx and r11
pop r11 ; syscall's return value in rax
pop rcx
ret
@read_stdin:
push rdi
push rsi
push rdx
mov rdi,STDIN ; file handle to read. STDIN = 1.
lea rsi,[input_buffer]
mov rdx,input_buffer_length ; length of string
mov rax,NR_read ; number of syscall (0)
call @do_syscall
sub rax,1 ; get the number of writable characters.
pop rdx
pop rsi
pop rdi
ret
_start: ; linker entry point
call @read_stdin
@end_program:
xor rdi,rdi
mov rax,NR_exit ; number of syscall (60)
syscall
section .data
input_buffer times 255 db 0
input_buffer_length equ $-input_buffer