is there a way to get human readable string (@"drwxr-xr-x" for example) from an NSFilePosixPermissions integer ?
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问题:
回答1:
The file system permissions attribute is simply an unsigned long value. The code below could obviously be made more efficient but it shows [more or less] what needs to be done to get the string you want:
// The indices of the items in the permsArray correspond to the POSIX
// permissions. Essentially each bit of the POSIX permissions represents
// a read, write, or execute bit.
NSArray *permsArray = [NSArray arrayWithObjects:@"---", @"--x", @"-w-", @"-wx", @"r--", @"r-x", @"rw-", @"rwx", nil];
NSFileManager *fm = [[[NSFileManager alloc] init] autorelease];
NSMutableString *result = [NSMutableString string];
NSDictionary *attrs = [fm attributesOfItemAtPath:@"some/path.txt" error:NULL];
if (!attrs)
return nil;
NSUInteger perms = [attrs filePosixPermissions];
if ([[attrs fileType] isEqualToString:NSFileTypeDirectory])
[result appendString:@"d"];
else
[result appendString:@"-"];
// loop through POSIX permissions, starting at user, then group, then other.
for (int i = 2; i >= 0; i--)
{
// this creates an index from 0 to 7
unsigned long thisPart = (perms >> (i * 3)) & 0x7;
// we look up this index in our permissions array and append it.
[result appendString:[permsArray objectAtIndex:thisPart]];
}
return result;
回答2:
Well I guess you can create an array like so:
NSArray *convertToAlpha = [NSArray arrayWithObjects:@"---",@"--x",@"-w-",@"--wx",@"r--",@"r-x",@"rw-",@"rwx", nil];
Then after tranlating the NSFilePosixPermissions to octal, split the resulting number into its componenet digits and use convertToAlpha to map each digit to its alphanumeric representation....