Is It Possible To Set Default Parameter Value On A

2019-02-16 18:07发布

问题:

ES6 introduces a bevy of convenient "syntactic sugar". Among them are the default parameter capabilities of JavaScript functions, as well as rest parameters. I'm finding that my console (or devTools) complains (i.e., throws an error) whenever attempting to set a default parameter value on a rest parameter. I've found surprisingly few references to this particular issue elsewhere and am wondering if 1.) it is possible to do so and 2.) why not (assuming it's not possible).

As an example, I've contrived a trivial (but, hopefully still purposeful) example. In this first iteration of the function, I've constructed the function such that it will work (which is to say, without giving the rest parameter a default value).

const describePerson = (name, ...traits) => `Hi, ${name}! You are ${traits.join(', ')}`;

describePerson('John Doe', 'the prototypical placeholder person');
// => "Hi, John Doe! You are the prototypical placeholder person"

However, now with the default:

const describePerson = (name, ...traits = ['a nondescript individual']) => `Hi, ${name}! You are ${traits.join(', ')}`;

describePerson('John Doe');
// => Uncaught SyntaxError: Unexpected token =

Any help is greatly appreciated.

回答1:

No, rest parameters cannot have a default initialiser. It is not allowed by the grammar because the initialiser would never be run - the parameter always gets assigned an array value (but possibly an empty one).

What you want to do could be achieved by either

function describePerson(name, ...traits) {
     if (traits.length == 0) traits[0] = 'a nondescript individual';
     return `Hi, ${name}! You are ${traits.join(', ')}`;
}

or

function describePerson(name, firstTrait = 'a nondescript individual', ...traits) {
     traits.unshift(firstTrait);
     return `Hi, ${name}! You are ${traits.join(', ')}`;
}

// the same thing with spread syntax:
const describePerson = (name, firstTrait = 'a nondescript individual', ...otherTraits) =>
    `Hi, ${name}! You are ${[firstTrait, ...otherTraits].join(', ')}`