I want to debug event handling code and would like to convert QEvent::Type
enum's value to a human-readable string. QEvent
has a Q_GADGET
macro, so presumably there's a way of pulling that off?
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问题:
回答1:
Recent versions of Qt do the right thing when outputting events to the debug stream, so the below isn't neccessary. If you get an error similar to warning C4273: 'operator <<' : inconsistent dll linkage
, it means that your version of Qt already supports this without need for the code below.
The Q_GADGET
macro adds a QMetaObject staticMetaObject
member to the class. The static metaobject's definition is generated by moc, and it - in the case of QEvent
- contains the enumeration information.
Below is an example of how to leverage that to give a more reasonable QDebug
output of events.
#include <QEvent>
#include <QMetaEnum>
#include <QDebug>
/// Gives human-readable event type information.
QDebug operator<<(QDebug str, const QEvent * ev) {
static int eventEnumIndex = QEvent::staticMetaObject
.indexOfEnumerator("Type");
str << "QEvent";
if (ev) {
QString name = QEvent::staticMetaObject
.enumerator(eventEnumIndex).valueToKey(ev->type());
if (!name.isEmpty()) str << name; else str << ev->type();
} else {
str << (void*)ev;
}
return str.maybeSpace();
}
Use example:
void MyObject::event(QEvent* ev) {
qDebug() << "handling an event" << ev;
}
回答2:
Q_GADGET and Q_ENUM can be combined to get the following template:
template<typename EnumType>
QString ToString(const EnumType& enumValue)
{
const char* enumName = qt_getEnumName(enumValue);
const QMetaObject* metaObject = qt_getEnumMetaObject(enumValue);
if (metaObject)
{
const int enumIndex = metaObject->indexOfEnumerator(enumName);
return QString("%1::%2::%3").arg(metaObject->className(), enumName, metaObject->enumerator(enumIndex).valueToKey(enumValue));
}
return QString("%1::%2").arg(enumName).arg(static_cast<int>(enumValue));
}
Example:
void MyObject::event(QEvent* ev)
{
qDebug() << ToString(ev->type());
}