Calling static method from object array variable

2019-02-16 09:29发布

问题:

In PHP you can call a class's static method from an object instance (which is contained in an array) like this:

$myArray['instanceOfMyClass']::staticMethod(); // works

But for some reason when I use the $this variable, I get a parsing error. E.g:

$this->myArray['instanceOfMyClass']::staticMethod(); // PARSING ERROR

Just to illustrate what I mean:

class MyClass{
    public static function staticMethod(){ echo "staticMethod called\n"; }
}

$myArray = array();
$myArray['instanceOfMyClass'] = new MyClass;
$myArray['instanceOfMyClass']::staticMethod(); // works

class RunCode
{
    private $myArray;

    public function __construct(){
        $this->myArray = array();
        $this->myArray['instanceOfMyClass'] = new MyClass;
        $this->myArray['instanceOfMyClass']::staticMethod(); // PARSING ERROR
    }
}

new RunCode;

Any ideas on how to get around this?

回答1:

You actually can use "->" to call static method:

$this->myArray['instanceOfMyClass']->staticMethod();


回答2:

This is a really interesting problem, it may even be a bug in PHP itself.

For a work around, use the KISS principle.

class RunCode
{
    private $myArray;

    public function __construct(){
        $this->myArray = array();
        $this->myArray['instanceOfMyClass'] = new MyClass;

        $instance = $this->myArray['instanceOfMyClass']
        $instance::staticMethod();
    }
}

Hope this helps!



回答3:

You will have to break up the one liner using a temporary variable, e.g.

$inst = $this->myArray['instanceOfMyClass'];
$inst::staticMethod()

This is one of many cases where PHP's compiler is not clever enough to understand nested expressions. The PHP devs have been improving this recently but there is still work to do.