Java subtract LocalTime

问题:

I have two LocalTime objects:

LocalTime l1 = LocalTime.parse("02:53:40");
LocalTime l2 = LocalTime.parse("02:54:27");

How can I found different in minutes between them?

回答1:

Use until or between, as described by the api

import java.time.LocalTime;
import static java.time.temporal.ChronoUnit.MINUTES;

public class SO {
    public static void main(String[] args) {
        LocalTime l1 = LocalTime.parse("02:53:40");
        LocalTime l2 = LocalTime.parse("02:54:27");
        System.out.println(l1.until(l2, MINUTES));
        System.out.println(MINUTES.between(l1, l2));
    }
}

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回答2:

Since Java 8 you can use Duration class. I think that gives the most elegant solution:

long elapsedMinutes = Duration.between(l1, l2).toMinutes();

回答3:

I do this with ChronoUnit

long minutesBetween = ChronoUnit.MINUTES.between(l1,l2);

Example

    LocalTime localTime=LocalTime.now();
    LocalTime localTimeAfter5Minutes=LocalTime.now().plusMinutes(5);
    Long minutesBetween=ChronoUnit.MINUTES.between(localTime,localTimeAfter5Minutes);
    System.out.println("Diffrence between time in munutes : "+minutesBetween);

Output

Diffrence between time in munutes : 5

回答4:

You could do this:

long dif = Math.abs (l1.getLocalMillis () - l2.getLocalMillis ());
TimeUnit.MINUTES.convert (dif, TimeUnit.MILLISECONDS);