When using map() with enumerate(), Swift will decompose the enumerate tuple:
map(enumerate([1,2,3])) { (index, element) in
index + element
}
However, this does not appear to work alongside an additional closure parameter (e.g., with reduce()):
reduce(enumerate([1,2,3]), 0) { (accum, (index, element)) in
accum + index + element
}
This fails with error: use of undeclared type 'index'
.
Am I missing something simple, or does Swift simply not allow decomposing a tuple alongside an additional parameter? I have tried this in 1.1 and 1.2. (For now, I am using the shorthand argument names.)
The answer is "Swift simply not allow it". You can't decompose nested tuple like that.
For example, this code compiles, but we cannot access j
or k
:
func foo(i: Int, (j: Int, k: Int) ) {
// println(j)
// ^ error: use of unresolved identifier 'j'
}
foo(1, (2, 3))
Because, in this code, (j: Int, k: Int)
is just a type, and the received tuple itself does not have a name. You have to write like this instead:
func foo(i: Int, x: (j: Int, k: Int) ) {
println(x.j)
}
foo(1, (1, 2))
In the same way, this compiles, but it's useless.
reduce(enumerate([12,42,84]), 0) { (accum, (index:Int, element:Int)) in
Instead, you have to receive the tuple itself, then decompose it if you want:
reduce(enumerate([12,42,84]), 0) { (accum, enumerated) in
println(enumerated.element)
let (index, element) = enumerated