This is my code to convert byte data to float. I tried every answers given in this site. I am getting exponential value for this "<44fa0000>" byte data
static func returnFloatValue(mutableData:NSMutableData)->Float
{
let qtyRange = mutableData.subdataWithRange(NSMakeRange(0, 4))
let qtyString = String(qtyRange)
let qtyTrimString = qtyString.stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "<>"))
let qtyValue = Float(strtoul(qtyTrimString, nil, 16)/10)
return qtyValue
}
Thanks
<44fa0000>
is the big-endian memory representation of the
binary floating point number 2000.0
. To get the number back from
the data, you have to read it into an UInt32
first, convert from
big-endian to host byteorder, and then cast the result to
a Float
.
In Swift 2 that would be
func floatValueFromData(data: NSData) -> Float {
return unsafeBitCast(UInt32(bigEndian: UnsafePointer(data.bytes).memory), Float.self)
}
Example:
let bytes: [UInt8] = [0x44, 0xFA, 0x00, 0x00]
let data = NSData(bytes: bytes, length: 4)
print(data) // <44fa0000>
let f = floatValueFromData(data)
print(f) // 2000.0
In Swift 3 you would use Data
instead of NSData
, and the
unsafeBitCast
can be replaced by the Float(bitPattern:)
initializer:
func floatValue(data: Data) -> Float {
return Float(bitPattern: UInt32(bigEndian: data.withUnsafeBytes { $0.pointee } ))
}
Use this function:
static func returnFloatValue(data: NSMutableData) -> Float {
let bytes = [UInt8](data as Data)
var f: Float = 0
memcpy(&f, bytes, 4)
return f
}
And you can see it in action here:
var initialValue: Float = 19.200
let data = NSMutableData(bytes: &initialValue, length: 4)
func returnFloatValue(data: NSMutableData) -> Float {
let bytes = [UInt8](data as Data)
var f: Float = 0
memcpy(&f, bytes, 4)
return f
}
var result:Float = returnFloatValue(data: data)
print("f=\(result)")// f=19.2