I'm trying to define an optional query parameter that will map to a Long
, but will be null
when it is not present in the URL:
GET /foo controller.Foo.index(id: Long ?= null)
... and I essentially want to check if it was passed in or not:
public static Result index(Long id) {
if (id == null) {...}
...
}
However, I'm getting a compilation error:
type mismatch; found : Null(null) required: Long Note that implicit
conversions are not applicable because they are ambiguous: both method
Long2longNullConflict in class LowPriorityImplicits of type (x:
Null)Long and method Long2long in object Predef of type (x: Long)Long
are possible conversion functions from Null(null) to Long
Why can't I do this, assigning null
to be a default value for an expected Long
optional query parameter? What's an alternative way to do this?
Remember that the optional query parameter in your route is of type scala.Long
, not java.lang.Long
. Scala's Long type is equivalent to Java's primitive long
, and cannot be assigned a value of null
.
Changing id
to be of type java.lang.Long
should fix the compilation error, and is perhaps the simplest way to resolve your issue:
GET /foo controller.Foo.index(id: java.lang.Long ?= null)
You could also try wrapping id
in a Scala Option
, seeing as this is the recommended way in Scala of handling optional values. However I don't think that Play will map an optional Scala Long to an optional Java Long (or vice versa). You'll either have to have a Java type in your route:
GET /foo controller.Foo.index(id: Option[java.lang.Long])
public static Result index(final Option<Long> id) {
if (!id.isDefined()) {...}
...
}
Or a Scala type in your Java code:
GET /foo controller.Foo.index(id: Option[Long])
public static Result index(final Option<scala.Long> id) {
if (!id.isDefined()) {...}
...
}
In my case I use a String variable.
Example :
In my route :
GET /foo controller.Foo.index(id: String ?= "")
Then I convert in my code with a parser to Long --> Long.parseLong.
But I agree that the method of Hristo is the best.