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问题:
public String size(int size){
String hrSize = "";
int k = size;
double m = size/1024;
double g = size/1048576;
double t = size/1073741824;
DecimalFormat dec = new DecimalFormat("0.00");
if (k>0)
{
hrSize = dec.format(k).concat("KB");
}
if (m>0)
{
hrSize = dec.format(m).concat("MB");
}
if (g>0)
{
hrSize = dec.format(g).concat("GB");
}
if (t>0)
{
hrSize = dec.format(t).concat("TB");
}
return hrSize;
}
This is a method that should return size in GB,MB, KB or TB. Input value is in KB.
for example result for 1245 should be like 1.21MB but what I get is 1.00MB.
回答1:
You are performing integer division
. So the result of division is also integer
. And fractional part is truncated.
so, 1245 / 1024 = 1
Change your division to floating point division
: -
double m = size/1024.0;
double g = size/1048576.0;
double t = size/1073741824.0;
Also, your comparison is faulty. You should do the comparison with 1
.
if (m > 1), if (t > 1), if (g > 1)
Ideally I would change your comparison to: -
if (t > 1) {
hrSize = dec.format(t).concat("TB");
} else if (g > 1) {
hrSize = dec.format(g).concat("GB");
} else if (m > 1) {
hrSize = dec.format(m).concat("MB");
} else {
hrSize = dec.format(size).concat("KB");
}
You need to compare with the higher unit first, and then move to the lower one.
回答2:
A modified version. Only calls format once. Includes "Bytes".
public static String formatFileSize(long size) {
String hrSize = null;
double b = size;
double k = size/1024.0;
double m = ((size/1024.0)/1024.0);
double g = (((size/1024.0)/1024.0)/1024.0);
double t = ((((size/1024.0)/1024.0)/1024.0)/1024.0);
DecimalFormat dec = new DecimalFormat("0.00");
if ( t>1 ) {
hrSize = dec.format(t).concat(" TB");
} else if ( g>1 ) {
hrSize = dec.format(g).concat(" GB");
} else if ( m>1 ) {
hrSize = dec.format(m).concat(" MB");
} else if ( k>1 ) {
hrSize = dec.format(k).concat(" KB");
} else {
hrSize = dec.format(b).concat(" Bytes");
}
return hrSize;
}
回答3:
I love this:
public static String getDynamicSpace(long diskSpaceUsed)
{
if (diskSpaceUsed <= 0) {
return "0";
}
final String[] units = new String[] { "B", "KiB", "MiB", "GiB", "TiB" };
int digitGroups = (int) (Math.log10(diskSpaceUsed) / Math.log10(1024));
return new DecimalFormat("#,##0.#").format(diskSpaceUsed / Math.pow(1024, digitGroups))
+ " " + units[digitGroups];
}
回答4:
The problem is that you're using integer division. Change your code to:
double m = size/1024.0;
double g = size/1048576.0;
double t = size/1073741824.0;
In your original code, double m = size/1024
would divide the integer size
by 1024
, truncate the result to an integer, and only then convert it to double
. This is why the fractional part was getting lost.
回答5:
You are performing integer division,
i.e., 31/15 will result in 2, not 2.whatever
just append the number with D
or d
which denotes it as a double and you will be fine
double m = size/1024D;
double g = size/1048576D;
double t = size/1073741824D;
回答6:
Its not easy to get that right. Rohit Jain mentioned the integer operation. Also rounding can be an issue, as always rounding down may not be desirable. I would advise to go for an available solution like in the triava library.
It can format numbers with arbitrary precision, in 3 different systems (SI, IEC, JEDEC) and various output options. Here are some code examples from the triava unit tests:
UnitFormatter.formatAsUnit(1126, UnitSystem.SI, "B");
// = "1.13kB"
UnitFormatter.formatAsUnit(2094, UnitSystem.IEC, "B");
// = "2.04KiB"
Printing exact kilo, mega values (here with W = Watt):
UnitFormatter.formatAsUnits(12_000_678, UnitSystem.SI, "W", ", ");
// = "12MW, 678W"
You can pass a DecimalFormat to customize the output:
UnitFormatter.formatAsUnit(2085, UnitSystem.IEC, "B", new DecimalFormat("0.0000"));
// = "2.0361KiB"
For arbitrary operations on kilo or mega values, you can split them into components:
UnitComponent uc = new UnitComponent(123_345_567_789L, UnitSystem.SI);
int kilos = uc.kilo(); // 567
int gigas = uc.giga(); // 123
回答7:
String[] fileSizeUnits = {"bytes", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB"};
public String calculateProperFileSize(double bytes){
String sizeToReturn = "";// = FileUtils.byteCountToDisplaySize(bytes), unit = "";
int index = 0;
for(index = 0; index < fileSizeUnits.length; index++){
if(bytes < 1024){
break;
}
bytes = bytes / 1024;
}
System.out.println("Systematic file size: " + bytes + " " + fileSizeUnits[index]);
sizeToReturn = String.valueOf(bytes) + " " + fileSizeUnits[index];
return sizeToReturn;
}
Just add more file units (if any missing), and you will see unit size upto that unit (if your file has that much length)
回答8:
My basic version (you CAN define some constants instead of computing POW all the time):
public static String GetFolderSizeHuman(long aBytes)
{
if (aBytes < 1024 * 1024)
return aBytes + " KB";
else if (aBytes < Math.pow(2, 20) * 1024)
return (int) aBytes / Math.pow(2, 20) + " MB";
else if (aBytes < Math.pow(2, 30) * 1024 )
return kGbTbFormatter.format(aBytes / Math.pow(2, 30)) + " GB";
else if (aBytes < Math.pow(2, 40) * 1024)
return kGbTbFormatter.format(aBytes / Math.pow(2, 40)) + " TB";
else return "N/A (1TB?)";
}
回答9:
bickster's answer works quite alright but the problem with it is that it returns results like 45.00 Bytes
and 12.00 KB
. In my opinion, the last decimal digits should be removed if they are zeros. So instead of 45.00 Bytes
and 12.00 KB
, you get 45 B
and 12 KB
(notice that Bytes
has been changed to B
. This is just for uniformity since we have KB, MB etc and not Kilobytes, Megabytes etc).
private boolean isDouble(double value) {
if (value % 1 == 0) {
Log.d(TAG, "value is " + value + " and is not double");
return false;
} else {
Log.d(TAG, "value is " + value + " and is double");
return true;
}
}
The above method simply checks if the value has zeros as decimal digits.
private String formatFileSize(long size) {
String hrSize = null;
double b = size;
double k = size/1024.0;
double m = ((size/1024.0)/1024.0);
double g = (((size/1024.0)/1024.0)/1024.0);
double t = ((((size/1024.0)/1024.0)/1024.0)/1024.0);
DecimalFormat dec1 = new DecimalFormat("0.00");
DecimalFormat dec2 = new DecimalFormat("0");
if (t>1) {
hrSize = isDouble(t) ? dec1.format(t).concat(" TB") : dec2.format(t).concat(" TB");
} else if (g>1) {
hrSize = isDouble(g) ? dec1.format(g).concat(" GB") : dec2.format(g).concat(" GB");
} else if (m>1) {
hrSize = isDouble(m) ? dec1.format(m).concat(" MB") : dec2.format(m).concat(" MB");
} else if (k>1) {
hrSize = isDouble(k) ? dec1.format(k).concat(" KB") : dec2.format(k).concat(" KB");
} else {
hrSize = isDouble(b) ? dec1.format(b).concat(" B") : dec2.format(b).concat(" B");
}
return hrSize;
}
回答10:
class ConverterUtils{
public static void main(String[] args) {
System.out.println(getSize(1234567));
}
public static String getSize(long size) {
String s = "";
double kb = size / 1024;
double mb = kb / 1024;
double gb = kb / 1024;
double tb = kb / 1024;
if(size < 1024) {
s = size + " Bytes";
} else if(size >= 1024 && size < (1024 * 1024)) {
s = String.format("%.2f", kb) + " KB";
} else if(size >= (1024 * 1024) && size < (1024 * 1024 * 1024)) {
s = String.format("%.2f", mb) + " MB";
} else if(size >= (1024 * 1024 * 1024) && size < (1024 * 1024 * 1024 * 1024)) {
s = String.format("%.2f", gb) + " GB";
} else if(size >= (1024 * 1024 * 1024 * 1024)) {
s = String.format("%.2f", tb) + " TB";
}
return s;
}
}
To better understand - https://www.techspot.com/news/68482-quickly-convert-between-storage-size-units-kb-mb.html