using EclipseLink as JPA 2.0 provider, I can obtain a JDBC connection by simply calling
Connection con = entityManager.unwrap(Connection.class);
But I'm unsure what I'm responsible for. Do I have to close the connection after submitting my queries? Or are I'm not allowed to close the connection, because EclipseLink also uses this connection internally. Or does it not care, because EclipseLink observes my behaviour and closes the connection automatically if I don't do it?
If you are in the context of a JPA transaction the connection will be managed by the provider (EclipseLink). If you are outside of a transaction you are responsible for managing the connection yourself.
See the following link for additional information:
http://wiki.eclipse.org/EclipseLink/Examples/JPA/EMAPI#Getting_a_JDBC_Connection_from_an_EntityManager
But I'm unsure what I'm responsible for. Do I have to close the
connection after submitting my queries? Or are I'm not allowed to
close the connection, because EclipseLink also uses this connection
internally.
A good and valid question. It seems that the documentation is lacking the semantics of the unwrap()
calls.
Regarding EclipseLink, according from what I got from the source:
EclipseLink gives you a reference to the currently active connection
which it uses for the currently active client session transaction. If no transaction is active, a new will be created, associated with the session and returned from the unwrap()
method.
As a result, IMHO, a commit/rollback of such a obtained Connection
may lead to undefined behavior and/or exceptions. Same is true for executing DML which changed records have been previously cached by eclipselink internal caches or for which managed entities exist.
So when using this API, especially if the underlying transaction is dirty, be careful.
If you can refer to internal eclipselink classes, you can access eclipselink internal connection pool to get a Connection
exclusively (have a look at org.eclipse.persistence.sessions.server.ServerSession.getConnectionPool(String)
).