Convert Unix timestamp to a readable date in Perl

问题:

I have some Unix timestamps (for example, 1357810480, so they're mainly in the past). How can I transform them into a readable date-format using Perl?

回答1:

You can use localtime for that.

my ($sec, $min, $hour, $mday, $mon, $year, $wday, $yday, $isdst) = localtime($unix_timestamp);

回答2:

Quick shell one-liner:

perl -le 'print scalar localtime 1357810480;'
Thu Jan 10 10:34:40 2013

Or, if you happen to have the timestamps in a file, one per line:

perl -lne 'print scalar localtime $_;' <timestamps

回答3:

A perfect use for Time::Piece (standard in Perl since 5.10).

use 5.010;
use Time::Piece;

my $unix_timestamp = 1e9; # for example;

my $date = localtime($unix_timestamp)->strftime('%F %T'); # adjust format to taste

say $date; # 2001-09-09 02:46:40

回答4:

You could use

my ($S, $M, $H, $d, $m, $Y) = localtime($time);
$m += 1;
$Y += 1900;
my $dt = sprintf("%04d-%02d-%02d %02d:%02d:%02d", $Y,$m, $d, $H, $M, $S);

But it's a bit simpler with strftime:

use POSIX qw( strftime );
my $dt = strftime("%Y-%m-%d %H:%M:%S", localtime($time));

localtime($time) can be substituted with gmtime($time) if it's more appropriate.

回答5:

Or, if you have a file with embedded timestamps, you can convert them in place with:

$ cat [file] | perl -pe 's/([\d]{10})/localtime $1/eg;'

回答6:

I liked JDawg's answer but couldn't get it to work properly on a RHEL system I was working on. I was able to get this to work. Hopefully this will help someone. It displays the contents of a file with the converted timestamps in place.

cat filename | perl -pe 's/(\d+)/localtime($1)/e'