Python list sort in descending order

问题:

How can I sort this list in descending order?

timestamp = [
    \"2010-04-20 10:07:30\",
    \"2010-04-20 10:07:38\",
    \"2010-04-20 10:07:52\",
    \"2010-04-20 10:08:22\",
    \"2010-04-20 10:08:22\",
    \"2010-04-20 10:09:46\",
    \"2010-04-20 10:10:37\",
    \"2010-04-20 10:10:58\",
    \"2010-04-20 10:11:50\",
    \"2010-04-20 10:12:13\",
    \"2010-04-20 10:12:13\",
    \"2010-04-20 10:25:38\"
]

回答1:

In one line, using a lambda:

timestamp.sort(key=lambda x: time.strptime(x, \'%Y-%m-%d %H:%M:%S\')[0:6], reverse=True)

---

Passing a function to list.sort:

def foo(x):
    return time.strptime(x, \'%Y-%m-%d %H:%M:%S\')[0:6]

timestamp.sort(key=foo, reverse=True)

回答2:

This will give you a sorted version of the array.

sorted(timestamp, reverse=True)

If you want to sort in-place:

timestamp.sort(reverse=True)

回答3:

You can simply do this:

timestamp.sort(reverse=True)

回答4:

Since your list is already in ascending order, we can simply reverse the list.

>>> timestamp.reverse()
>>> timestamp
[\'2010-04-20 10:25:38\', 
\'2010-04-20 10:12:13\', 
\'2010-04-20 10:12:13\', 
\'2010-04-20 10:11:50\', 
\'2010-04-20 10:10:58\', 
\'2010-04-20 10:10:37\', 
\'2010-04-20 10:09:46\', 
\'2010-04-20 10:08:22\',
\'2010-04-20 10:08:22\', 
\'2010-04-20 10:07:52\', 
\'2010-04-20 10:07:38\', 
\'2010-04-20 10:07:30\']

回答5:

you simple type:

timestamp.sort()
timestamp=timestamp[::-1]