Here is my server.py:
import BaseHTTPServer
import SocketServer
class TestRequestHandler(BaseHTTPServer.BaseHTTPRequestHandler):
def do_GET(self):
self.wfile.write("hello world at %s" % __file__)
server = BaseHTTPServer.HTTPServer(('', 10000), TestRequestHandler)
#server = SocketServer.ThreadingTCPServer(('', 8888), TestRequestHandler)
server.serve_forever()
Here is my client.py:
import urllib2
req = urllib2.Request('http://127.0.0.1:10000/')
handle = urllib2.urlopen(req)
content = handle.read()
Then I start server.py, it works.
When I start client.py, I get this error on Windows 7, Python 2.6:
Traceback (most recent call last):
File "D:\Dropbox\Forge\urllib-error\client.py", line 3, in <module>
handle = urllib2.urlopen(req)
File "C:\Python26\lib\urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python26\lib\urllib2.py", line 391, in open
response = self._open(req, data)
File "C:\Python26\lib\urllib2.py", line 409, in _open
'_open', req)
File "C:\Python26\lib\urllib2.py", line 369, in _call_chain
result = func(*args)
File "C:\Python26\lib\urllib2.py", line 1161, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "C:\Python26\lib\urllib2.py", line 1136, in do_open
raise URLError(err)
urllib2.URLError: <urlopen error [Errno 10013] An attempt was made to access a socket in a way forbidden by its access permissions>
When I open http://127.0.0.1:10000/ from a browser, it works. It means server is fine.
When I replace http://127.0.0.1:10000/ with http://127.0.0.1/ or http://127.0.0.1:80/ in client.py, everything works fine (this is another web server on port 80 - apache).
What do I do wrong?
UPD: Same error when I use this client2.py:
import urllib2
handle = urllib2.urlopen('http://127.0.0.1:10000/')
content = handle.read()
UPD: Problem solved. It was my firewall. When disabled, everything works. Stupid, stupid me. Thanks for reading :-)