When I'm stopped in the debugger in Xcode 6, how can I view the value of a local Swift constant declared with let
?
If I create a brand new Swift project in Xcode 6 and add the following two lines to application(_:didFinishLaunchingWithOptions:)
in the app delegate:
let someConstant = 5
var someVariable = 6
…then run the app and break immediately after these lines, this is what I see in the variables view of the debugger:
Why does the variable display its value, while the constant does not? (And why is the constant listed twice?)
If, in the LLDB console, I try p
, po
, or fr v
on someConstant
(all of which correctly display the value of someVariable
), I get the following:
I'm aware that I can print the value in the debugger by using println
in my source code, but I'd really rather not have to have the foresight to do that every time I simply want to inspect a value I've declared as a constant. (Even running expr println(someConstant)
in the LLDB console produced the same "unresolved identifier" error as p
and po
.)
This should be easy. What am I missing?