For example purposes...
for x in range(0,9):
string\'x\' = \"Hello\"
So I end up with string1, string2, string3... all equaling \"Hello\"
For example purposes...
for x in range(0,9):
string\'x\' = \"Hello\"
So I end up with string1, string2, string3... all equaling \"Hello\"
Sure you can; its called a dictionary:
d={}
for x in range(1,10):
d[\"string{0}\".format(x)]=\"Hello\"
In [7]: d[\"string5\"]
Out[7]: \'Hello\'
In [8]: d
Out[8]:
{\'string1\': \'Hello\',
\'string2\': \'Hello\',
\'string3\': \'Hello\',
\'string4\': \'Hello\',
\'string5\': \'Hello\',
\'string6\': \'Hello\',
\'string7\': \'Hello\',
\'string8\': \'Hello\',
\'string9\': \'Hello\'}
I said this somewhat tongue in check, but really the best way to associate one value with another value is a dictionary. That is what it was designed for!
It is really bad idea, but...
for x in range(0, 9):
globals()[\'string%s\' % x] = \'Hello\'
and then for example:
print(string3)
will give you:
Hello
However this is bad practice. You should use dictionaries or lists instead, as others propose. Unless, of course, you really wanted to know how to do it, but did not want to use it.
It\'s simply pointless to create variable variable names. Why?
exec
or globals()
exec/globals()
againUsing a list is much easier:
# 8 strings: `Hello String 0, .. ,Hello String 8`
strings = [\"Hello String %d\" % x for x in range(9)]
for string in strings: # you can loop over them
print string
print string[6] # or pick any of them
Don\'t do this use a dictionary
import sys
this = sys.modules[__name__] # this is now your current namespace
for x in range(0,9):
setattr(this, \'string%s\' % x, \'Hello\')
print string0
print string1
print string2
print string3
print string4
print string5
print string6
print string7
print string8
don\'t do this use a dict
globals() has risk as it gives you what the namespace is currently pointing to but this can change and so modifying the return from globals() is not a good idea
One way you can do this is with exec()
. For example:
for k in range(5):
exec(f\'cat_{k} = k*2\')
print(cat_0)
0
print(cat_1)
2
print(cat_2)
4
print(cat_3)
6
print(cat_4)
8
Here I am taking advantage of the handy f string formatting in python 3.6+
I would use a list:
string = []
for i in range(0, 9):
string.append(\"Hello\")
This way, you would have 9 \"Hello\" and you could get them individually like this:
string[x]
Where x
would identify which \"Hello\" you want.
So, print(string[1])
would print Hello
.