Python Requests, how to bind to different source i

问题:

This question already has an answer here:

• Requests, bind to an ip 1 answer

I'm trying to learn some python, and i'm having issues with the logic in what I want to test. Currently my code is written in a way that binding to source_address doesn't change when the process starts

import socket
import requests

real_create_conn = socket.create_connection

def set_src_addr(*args):
    address, timeout = args[0], args[1]
    source_address = ('201.X.X.1', 0)
    return real_create_conn(address, timeout, source_address)

socket.create_connection = set_src_addr

r = requests.get('http://www.mywebpage.com/main')
print r.status_code 
if r.status_code == 404
   print "Webpage Down!"

r = requests.get('http://www.mywebpage.com/blog')
print r.status_code 
if r.status_code == 204
   print "Error occured!"

I'm looking to do something like this where

import socket
import requests


While 1: 

      #bind to source address 201.X.X.1
      #Send request to main webpage
      #print result
      time.sleep(300) # 5 minutes

      #bind to source address 201.X.X.12
      #Send request to blog webpage
      #print result
      time.sleep(300) # 5 minutes

回答1:

For each request, there is no elegant solution, but you'll need to use a requests Session object and mount a new transport adapter for each request.

You can find example code for the transport adapter in this issue comment, or you can use the adapter included in the requests-toolbelt package, like so

import requests
from requests_toolbelt.adapters import source

responses = []
s = requests.Session()
for source_ip, url in list_of_sources_and_urls:
    new_source = source.SourceAddressAdapter(source_ip)
    s.mount('http://', new_source)
    s.mount('https://', new_source)
    responses.append(s.get(url))

That assumes that list_of_sources_and_urls looks like

 [('127.0.0.1', 'https://google.com'),
  ('255.255.254.0', 'https://yahoo.com'),
  # ...
  ]