Multiple if statements in a lambda function

问题:

I am trying to use 3 if statements within a python lambda function. Here is my code:

y=lambda symbol: 'X' if symbol==True 'O' if symbol==False else ' '

I Have been able to get two if statements to work just fine e.g.

x=lambda cake: "Yum" if cake=="chocolate" else "Yuck"

Essentially, I want a lambda function to use if statements to return 'X' if the symbol is True, 'O' if it is false, and ' ' otherwise. I'm not even sure if this is even possible, but I haven't been able to find any information on the internet, so I would really appreciate any help :)

回答1:

You are missing an else before 'O'. This works:

y = lambda symbol: 'X' if symbol==True else 'O' if symbol==False else ' '

However, I think you should stick to Adam Smith's approach. I find that easier to read.

回答2:

You can use an anonymous dict inside your anonymous function to test for this, using the default value of dict.get to symbolize your final "else"

y = lambda sym: {False: 'X', True: 'Y'}.get(sym, ' ')