subprocess.Popen : how to pass a list as argument

问题:

I just need a hint on how to do things properly.

Say I have a script called script.py which uses a list of names as argument ["name1", "name2", etc. ].

I want to call this script from another script using the subprocess module. So what I would like to do is the following :

myList = ["name1", "name2", "name3"]
subprocess.Popen(["python", "script.py", myList])

Of course that doesn't work because the subprocess.Popen method requires a list of strings as arguments. So I considered doing the following :

subprocess.Popen(["python", "script.py", str(myList)])

Now the process starts but it doesn't work because it has a string as argument and not a list. How should I fix that properly?

回答1:

Concatenate them using + operator.

myList = ["name1", "name2", "name3"]
subprocess.Popen(["python", "script.py"] + myList)

BTW, if you want use same python program, replace "python" with sys.executable.

回答2:

Thanks for the quick answer falsetru. It doesn't work directly but I understand how to do. You're suggestion is equivalent to doing :

subprocess.Popen(["Python","script.py","name1","name2","name3"])

Where I have 3 arguments that are the strings contained in my original list.

All I need to do in my script.py file is to build a new list from each argument received by doing the following :

myList = sys.argv[1:]

myList is now the same than the one I had initially!

["name1","name2","name3"]

Don't know why I didn't think about it earlier!